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2 years ago

In each diagram I'm to label the reaction forces I'm a bit confused with the question

Physics

1 answer:

Furkat [3]2 years ago

5 0

If what I see is correct the middle picture is the answer

If you throw a bowling ball at the pins, the pins will fall down (that is if you don't miss). The force of the ball will knock down the pins, therefore the pins are reacting to the force of the bowling ball which is reacting to how the person threw it. Does that make sense?

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------forces,hold electrons to nuclei,atoms and molecules together to give rise to bulk matter

ch4aika [34]

The force is known as electrostatic force (or electric force)

3 0

2 years ago

a pool ball leaves a 0.60 meter high table with an initial high table with an initial horizontal velocity of 2.4m/s. predict the

timurjin [86]

Ball leaves the table of height 0.60 m

Initial speed of the ball is in horizontal direction which is 2.4 m/s

Now here we can say that time taken by the ball to hit the ground will be given by kinematics equation in vertical direction

$\Delta y = v_y*t + \frac{1}{2}at^2$

here in y direction we can say

$\Delta y = 0.60 m$

$v_y = 0$

$a = 9.8 m/s^2$ due to gravity

now from above equation we have

$0.60 = 0 + \frac{1}{2}*9.8*t^2$

$t = 0.35 s$

Now in the same time the distance that ball move in horizontal direction is given as

$d = v_x* t$

given that

$v_x = 2.4 m/s$

$d = 2.4 * 0.35$

$d = 0.84 m$

So it will move a total distance of 0.84 m where it will land

5 0

2 years ago

The cannon on a battleship can fire a shell a maximum distance of 26.0 km.

Alla [95]

It is possible to demonstrate that the maximum distance occurs when the angle at which the projectile is fired is $\theta = 45^{\circ}$ .
In fact, the laws of motions on both x- and y- directions are
$S_x(t)= v_0 cos \theta t$
$S_y(t)= v_0 \sin \theta t - \frac{1}{2} gt^2$
From the second equation, we get the time t at which the projectile hits the ground, by requiring $S_y(t)=0$ , and we get:
$t= \frac{2 v_0 \sin \theta}{g}$
And inserting this value into Sx(t), we find
$S_x(t) = 2 \frac{v_0^2}{g} \sin \theta \cos \theta= \frac{v_0^2}{g} \sin (2\theta)$
And this value is maximum when $\theta=45^{\circ}$ , so this is the angle at which the projectile reaches its maximum distance.

So now we can take again the law of motion on the x-axis
$S_x(t)= \frac{v_0^2}{g} \sin (2\theta)$
And by using $S_x = 26 km=26000 m$ , we find the value of the initial velocity v0:
$v_0 = \sqrt{ \frac{S_x g}{\sin (2\theta)} } = \sqrt{ \frac{(26000m)(9.81m/s^2)}{\sin (2\cdot 45^{\circ})} } =505 m/s$

8 0

2 years ago

True or False The process of waves dropping sand on beach is called deposition

Vladimir [108]

I believe the answer is True have a good day!

7 0

2 years ago

Read 2 more answers

The Olympias is a reconstruction of a trireme, a type of Greek galley ship used over 2000 years ago. The power P (in kilowatts)

TEA [102]

Answer:

7.13559 knots