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3 years ago

The process by which land remove surface materials is called

Physics

2 answers:

yuradex [85]3 years ago

4 0

The answer is Deflation

Citrus2011 [14]3 years ago

3 0

Answer:

Deflation

Explanation:

The process by which wind removes surface materials is called deflation.

Deflation is a process by which wind erodes the Earth's exterior and the regions which experience severe erosion are called deflation zones.

deflation originates by the erosive force of a wind that removes the loosened area and this process is facilitated by a dry climate and a loss of vegetative cover that helps to lose the sediment.

deflation is common in the arid regions.

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Stells [14]

Answer:

1.1 lbs

Explanation:

To convert kg to lbs you multiply kilograms by 2.2. So 0.5kg × 2.2 equals to 1.1 lbs

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3 years ago

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sergejj [24]

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3 years ago

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Monochromatic light with a wavelength of 6.4 E -7 meter passes through two narrow slits, producing an interference pattern on a

seropon [69]

Answer:

The distance between the slits is given by 1.3 × $10^{-4}$ m

Given:

$\lambda = 6.4 \times 10^{-7} m$

D = 4 m

y = $2 \times 10^{-2} m$

m = 1

To find:

distance between slits, d = ?

Formula used:

y = $\frac{m \times \lambda \times D}{d}$

y = distance of first bright band from central maxima

D = distance between screen and source

d = distance between slits

$\lambda$ = wavelength

Solution:

distance of first bright band from central maxima is given by,

y = $\frac{m \times \lambda \times D}{d}$

y = distance of first bright band from central maxima

D = distance between screen and source

d = distance between slits

$\lambda$ = wavelength

Thus,

d = $\frac{m \times \lambda \times D}{y}$

d = $\frac{1 \times 6.4 \times 10^{-7} \times 4 }{2 \times 10^{-2} }$

d = 1.28 × $10^{-4}$

d = 1.3 × $10^{-4}$ m

The distance between the slits is given by 1.3 × $10^{-4}$ m

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3 years ago

Arigid body must rotate about an axis in order for it to have angular momentum about that axis. True False

kompoz [17]

Answer:

False

Explanation:

Let's consider the definition of the angular momentum,

$\vec{L} = I \vec{\omega}$

where $I = \int\limits_m r^2 dm = \lim_{n \to \infty} \sum\limits_{i=1}^n m_i r_i^2$ is the moment of inertia for a rigid body. Now, this moment of inertia could change if we change the axis of rotation, because "r" is defined as the distance between the puntual mass and the nearest point on the axis of rotation, but still it's going to have some value. On the other hand,

$\vec{\omega} = \frac{\vec{r} \times \vec{v}}{r^2}$ so $\vec{\omega} \neq 0$ unless $\vec{r}$ ║ $\vec{v}$ .

In conclusion, a rigid body could rotate about certain axis, generating an angular momentum, but if you choose another axis, there could be some parts of the rigid body rotating around the new axis, especially if there is a projection of the old axis in the new one.

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3 years ago