Question

Does anyone know how to work this out?

Answer 1

Answer:

$\frac{17}{14}*5$ = Approximately 6

Explanation:

What we need to know:

1. Given that this is a parallel circuit, each pathway will receive the full voltage from the source. Therefore, each pathway will receive 17V.

2. The current (I) stays the same for all loads in series. Therefore, I2 and I3 are equal since they are connected in series.

3. Ohm's law states that Voltage = Current × Resistance (V=IR)(I=V/R)(R=V/I)

1) Calculate the current for the path containing R2 and R3

$I_2_,_3=\frac{V_2_,_3}{R_2_,_3}\\I_2_,_3=\frac{17}{5+9}\\I_2_,_3=\frac{17}{14}$

Because the current running through this path is $\frac{17}{14}$ A, then I2 is $\frac{17}{14}$ A.

2) Use Ohm's Law by plugging in I2 and R2

$V_2=I_2*R_2\\V_2=\frac{17}{14} *5$

$V_2=6$ (approximate)

Therefore, V2 is approximately 6V.

I hope this helps!