The concentrations : 0.15 M
pH=11.21
<h3>Further explanation</h3>The ionization of ammonia in water :
NH₃+H₂O⇒NH₄OH
NH₃+H₂O⇒NH₄⁺ + OH⁻
The concentrations of all species present in the solution = 0.15 M
Kb=1.8 x 10⁻⁵
M=0.15
Explain how percent yield is calculated
1 answer:
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Answer: Amount of sodium chloride produced is 25.43 grams.
Explanation:
To calculate the moles:
Given: Mass of sodium = 10 g
Molar mass of sodium = 23g/mol
The balanced equation is:
By Stoichiometry of the reaction,
2 moles of sodium produces 2 moles of sodium chloride
So, 0.4347 moles of sodium will produce = of sodium chloride.
Molar mass of sodium chloride = 58.5 g/mol
Putting values in equation 1, we get:
Hence, amount of sodium chloride produced is 25.43 grams.