Answer:
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Explanation:
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Answer:
The molarity of this solution is 0.156 M
Explanation:
Step 1: Data given
Mass of Ba(OH)2 = 1.90 grams
Molar mass Ba(OH)2 = 171.34 g/mol
Volume of the solution = 71.1 mL = 0.0711 L
Step 2: Calculate moles Ba(OH)2
Moles Ba(OH)2 = mass Ba(OH)2 / molar mass Ba(OH)2
Moles Ba(OH)2 = 1.90 grams / 171.34 g/mol
Moles Ba(OH)2 = 0.0111 moles
Step 3: Calculate molarity
Molarity solutin = moles Ba(OH)2 / volume solution
Molarity solution = 0.0111 moles / 0.0711 L
Molarity solution = 0.156 M
The molarity of this solution is 0.156 M
Answer:
9400 Grams to Kilograms
To change the mass we use formula [kg] = [9400] / 1000
Answer:
Mass of arsenic chloride produced is 0.363 g
Explanation:
Given data:
Mass of arsenic chloride produced = ?
Mass of arsenic react = 0.150 g
Mass of chlorine = excess
Solution:
Chemical equation:
2As + 3Cl₂ → 2AsCl₃
First of all we will calculate the number of moles of arsenic.
Number of moles = mass/ molar mass
Number of moles = 0.150 g/ 75 g/mol
Number of moles = 0.002 mol
Now we will compare the moles of arsenic with arsenic chloride.
As : AsCl₃
2 : 2
0.002 : 0.002
Mass of arsenic chloride produced:
Mass = number of moles × molar mass
Mass = 0.002 × 181.28 g/mol
Mass = 0.363 g
