Pressure of Butane in the container at 135°C = 1.07 atm
Given:
The H°vap of butane is 24.3 kJ/mol.
starting out at 25 °C
Temperature at the end: 135 °C
2.3 atm of pressure
To Find:
The container's pressure
The perpendicular force per unit area, also known as the stress at a point within a confined fluid, is known as pressure in the physical sciences.
Equation of Clausius-Clapeyron
P2 = 1.07 atm and ln (P2/2.3 atm)
= - 24.3*110/8.31
The pressure in the container at 135°C (ΔH°vap ) is 1.07 atm
Learn more about Pressure here:
brainly.com/question/25736513
#SPJ4
C3H8 + 5O2 ------> 3CO2 + 4H2O
from reaction 1 mol 5 mol
given 1.82 mol x mol
x=(1.82*5)/1 = 9.10 mol CO2
a core of protons and neutrons surrounds by electrons
Mass of CO₂ produced : 58.67 g
<h3>Further explanation</h3>
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.
Reaction
CS₂ + 3O₂ -------> CO₂ + 2SO₂
mol of CO₂ based on mol of O₂ as a limiting reactant(CS₂ as an excess reactant)
From the equation, mol ratio of mol CO₂ : mol O₂ = 1 : 3, so mol CO₂ :
mass CO₂ (MW= 44 g/mol) :
Hi uhh i've never really typed in Spanish but here I go! :)
Un ano luz es equivalente a 9.467 PM
