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ivolga24 [154]
3 years ago
14

What is the atom formula for (NaPO3)6 ?

Chemistry
2 answers:
padilas [110]3 years ago
5 0

Answer:The formula for Sodium Hexametaphosphate is (NaPO3)6. It is a gathering of sodium polyphosphate polymers based on repeating NaPO3 units. It is a water ...

Chemical Formula‎: ‎Na6P6O18

Explanation:

Mrrafil [7]3 years ago
3 0

Answer:

Sodium Hexametaphosphate i

Explanation:

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During the dust bowl wind deposited surface minerals in a new location by what?
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"Saltation" which is the movement of hard particles such as sand over an uneven surface in a turbulent flow of air or water.
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Calculate the percent by mass of each element in LiClO2.<br><br> % Li: <br><br> % Cl: <br><br> % O:
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ok done. Thank to me :>

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What is neutron number for calcium ​
notka56 [123]

Answer:

20 neutrons

Explanation:

(not really any just look at a periodic table)

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If the initial volume is 55ml and the final volume after some rocks of sandstone are added is 65ml what is the volume of the chi
AfilCa [17]

Answer:

Volume = 10ml

Density = 1/5 g/ml or 0.20g/ml

Explanation:

The rocks are 10ml since the initial volume went up by 10.

Since density = mass/volume, you divide 2 by 10.

D = 2/10

D = 1/5 g/ml or 0.20g/ml

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7 0
3 years ago
Now you will solve the same problem as above, but using the quadratic formula instead of iterations, to show that the same value
Dafna1 [17]

Answer:

a: 1

b: 4.5x10⁻⁴

c: 1.125x10⁻⁶

[H₃O⁺] = 0.000859M

Explanation:

As HNO₂ is a weak acid, its equilibrium in water is:

HNO₂(aq) + H₂O(l) ⇄ H₃O⁺(aq) + NO₂⁻(aq)

Equilibrium constant, ka, is defined as:

ka = 4.5x10⁻⁴ = [H₃O⁺] [NO₂⁻] / [HNO₂] <em>(1)</em>

Equilibrium concentration of each specie are:

[HNO₂] = 0.00250M - x

[H₃O⁺] = x

[NO₂⁻] = x

Replacing in (1):

4.5x10⁻⁴ = x × x / 0.00250M - x

1.125x10⁻⁶ - 4.5x10⁻⁴x = x²

0 = x² + 4.5x10⁻⁴x - 1.125x10⁻⁶

As the quadratic equation is ax² + bx + c = 0

Coefficients are:

a: 1

b: 4.5x10⁻⁴

c: 1.125x10⁻⁶

Now, solving quadratic equation:

x = -0.0013 → False answer, there is no negative concentrations.

<em>x = 0.000859</em>

As [H₃O⁺] = x; <em>[H₃O⁺] = 0.000859M</em>

I hope it helps!

6 0
3 years ago
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