Calculate the length of AC

write an equation in slope intercept form for the line described. perpendicular to y = -1/2x + 2/3, passes through (2,3)

Alex17521 [72]

Step-by-step explanation:

Hey there!

Follow the steps to get answer.

Use one point formula and find 1st equation.
After that you find the slope of second equation.
Use the condition of perpendicular lines and find the slope of first equation.
Put slope value of equation in equation (i) and simplify them to get equation.

The equation of a line passing through point (2,3) is;

(y-3)= m1(x-2).......(i).

Another equation is;

$y = \frac{ - 1}{2} x + \frac{2}{3}$

2nd equation..

Now, From equation (ii)

We have;

Comparing equation (ii) with y = mx+c.

We get;

Slope = -1/2.

For perpendicular lines,

$m1 \times m2 = - 1$

$m1 \times \frac{ - 1}{2} = - 1$

Therefore the slope is 2.

Put value of slope (m1) in equation (i). We get;

$(y - 3) = 2(x - 2)$

Simplify them to get equation.

$(y - 3) = 2x - 4$

$y = 2x - 1$

Therefore the required equation is y = 2x-1.

Hope it helps..

4 0

3 years ago

How do i write an exponential equation with a vertical asymptote other that y=0

antiseptic1488 [7]

Lets say we have
P(x)/q(x)

vertical assymtotes are in the form x=something, not y=0
y=0 are horizontal assemtotes

so verticall assymtotes
reduce the fraction
set the denomenator equal to zero
those values that make the deomenator zero are the vertical assymtotes

the horizontal assymtote
when the degree of P(x)<q(x), then HA=0

when the degree of P(x)=q(x), then divide the leading coefient of P(x) by the leading coeficnet of q(x)
example, f(x)=(2x^2-3x+3)/(9x^2-93x+993), then HA is 2/9

ok so for vertical assymtote example
f(x)=x/(x^2+5x+6)
the VA's are at x=-3 and x=-2

horizontal assymtote
make degree same
f(x)=(3x^2-4)/(8x^2+9x),
the HA is 3/8
hope I helped, read the whole thing then ask eusiton

6 0

4 years ago

On a coordinate plane, kite W X Y Z is shown. Point W is at (negative 3, 3), point X is at (2, 3), point Y is at (4, negative 4)

Aloiza [94]

The perimeter of the kite is (10 + 2√53) units if the kite and the coordinates of the kite are point W is at (-3, 3), point X is at (2, 3), point Y is at (4, -4), and point Z is at (-3, -2).

<h3>What is quadrilateral?</h3>

It is defined as the four-sided polygon in geometry having four edges and four corners. Kite is quadrilateral, in which. Two pairs of congruent sides, and it has one pair of opposite congruent angles.

The figure is missing.

On a coordinate plane, kite WXYZ is shown (please refer to the picture)

We have a kite and the coordinates of the kite are:

Point W is at (-3, 3), point X is at (2, 3), point Y is at (4, -4), and point Z is at (-3, -2).

Using the distance formula we can find the distance between coordinates:

$\rm d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between W and X:

$\rm WX=\sqrt{(2+3)^2+(3-3)^2}$

WX = 5 units

Similarly, distance between X and Y:

XY = √53 units

YZ = √53 units

ZW = 5 units

Perimeter = sum of the all sides

Perimeter = 5 + √53 + √53 + 5

Perimeter = (10 + 2√53) units

Thus, the perimeter of the kite is (10 + 2√53) units if the kite and the coordinates of the kite are point W is at (-3, 3), point X is at (2, 3), point Y is at (4, -4), and point Z is at (-3, -2).

Learn more about the quadrilateral here:

brainly.com/question/6321910

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