Question

You are given a parallel plate capacitor that has plates of area 27 cm^2 which are separated by 0.0100 mm of nylon (dielectric constant x = 3.4). You are told to assume that this capacitor stores 011 mC of charge. Calculate what the applied voltage in kV should be for this capacitor

Answer 1

Answer:

Applied voltage should be 13.5396 kV

Explanation:

The charge stored by a capacitor when subjected to a potential difference 'v' across it's plates is given by

$Q=\frac{K\epsilon _{o} A}{d}V$

Solving for V we get

$V=\frac{Qd}{K\epsilon _{o}A}$

thus to store a charge of 0.11mC we solve for V as follows

Applying values we get

$V=\frac{0.11\times 10^{-3}\times 0.01\times 10^{-3}}{27\times 10^{-4}\times 3.4\times 8.85\times 10^{-12}}$

$\therefore V=13.5396kV$