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Ulleksa [173]
4 years ago
8

What is the change in atomic mass number when an atom emits an alpha particle?

Physics
1 answer:
natita [175]4 years ago
6 0

Answer:

Decreases by 4

Explanation:

  • An alpha particle is made of two protons and two neutrons. An alpha decay involves the ejection of an alpha particle from the nucleus.
  • Therefore since an alpha particles is equivalent to a helium nucleus, it involves the loss of 2 protons and 2 neutrons.
  • <em><u>Hence, we can conclude that when a nucleus emits an alpha particle, the mass number or the atomic mass decreases by 4 and the atomic number decreases by 2</u></em><em><u>.</u></em>
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A stone is dropped at t = 0. A second stone, with 6 times the mass of the first, is dropped from the same point at t = 59 ms. (a
xxTIMURxx [149]

Answer:y_{com}=0.707 m

v_{com}=3.713 m/s

Explanation:

Given

first stone mass is m

second stone mass is 6 m

distance traveled by  first stone in 430 ms

y_1=ut+\frac{at^2}{2}

y_1=0+\frac{g(0.43)^2}{2}

y_1=0.9069 m

Distance traveled by stone 2 in t=430-59=371 ms

y_2=ut+\frac{at^2}{2}

y_2=0+\frac{g(0.0.371)^2}{2}

y_2=0.674 m

velocity of first stone after t=0.43 s

v_1=u+at

v_1=0+9.8\times 0.43=4.214 m/s

velocity of second stone after t=0.371 s

v_2=u+at

v_2=0+9.8\times 0.371=3.63 m/s

Position of Center of mass of system

y=\frac{y_1m_1+y_2m_2}{m_1+m_2}

y=\frac{0.9069\times m+0.674\times 6m}{m+6m}

y=\frac{4.95m}{7m}=0.707 m

Velocity of COM

v_{com}=\frac{v_1m_1+v_2m_2}{m_1+m_2}

v_{com}=\frac{4.214\times m+3.63\times 6m}{m+6m}

v_{com}=3.713 m/s

6 0
4 years ago
Pls help ASAP !! Phyics
mina [271]

Answer:

Explanation:

Given

mass (m)= 20 kg

acceleration (a)= 10 m/s^2

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7 0
3 years ago
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trapecia [35]

Explanation:

The balanced chemical equation is given as:

              2H₂O₂  →  O₂  +  2H₂O

А  There are two peroxide molecules on the reactant side.

The statement is correct because the left hand side is the reactant side. We can read the reaction as;

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D Mass must be conserved so there are an equal number of molecules in the reactants and products.

E Mass must be conserved so there are an equal number of atoms in the reactants and products.

Since the chemical equation is balanced, choices D and E are correct. The reaction will have equal number of molecules and atoms on both sides of the expression.

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