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Mkey [24]
3 years ago
5

Show the mechanism for the following reaction conducted at –5 °C in CCl4: cyclohexene bromine yields a dibromocyclohexane Draw w

edge-and-dash bond stereochemical structures – including H atoms at a chirality center – and include charges, electrons, and curved arrows. Details count. Draw one enantiomer only for any racemates.

Chemistry
1 answer:
Darya [45]3 years ago
7 0

Answer:

See attachment.

Explanation:

In the first step, a cyclic structure with a positive bromine is formed. The bromine shares the positive charge with the two carbons that it is bonded to, so the carbons are partially positive.

The second bromine atom then attacks the carbon center, coming in from below the first bromine atom ("backside attack") where the antibonding orbital of the second bromine atom is.

The stereochemistry of the mechanism causes the final product to be an anti-dibromocyclohexane.

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A/1 * B/C = D
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Answer : 4.8 florins can you exchange for your 4 guilders.

Solution : Given,

The current exchange rate for every 2.4 florins is 2.0 guilders

As per question,

The exchange rate is 2.0 guilders for every 2.4 florins

The exchange rate is 1 guilders for every \frac{2.4}{2.0} florins

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3 0
3 years ago
I need titration curve of sebacic acid
RoseWind [281]

Answer:

is a plot showing the change in ph of the solution in the conical flask as the reagent is added from the burette

Explanation:

like, the ph of the solution at equivalence point is dependent on the strenght of the acid and strenght of the base used in the titration

7 0
3 years ago
8. Which of the following is TRUE about limiting and excess reactants?
Ivahew [28]
B. The limiting reactant determines the max amount of product that can be formed
5 0
3 years ago
What is the volume of a balloon of gas at 842 mm Hg and -23° C, if its volume is 915 mL at a pressure of 1,170 mm Hg and a tempe
garik1379 [7]
Answer:
             V₂  =  1070 mL or 1.07 L

Solution:

Data Given;
                  P₁  =  1170 mmHg

                  V₁  =  915 mL

                  T₁  =  24 °C  +  273 K  =  297 K

                  P₂  =  842 mmHg

                  V₂  =  ?

                  T₂  =  - 23 °C  +  273 K  =  250 K

According to Ideal gas equation,

                       P₁ V₁ / T₁  =  P₂ V₂ / T₂

Solving for V₂,

                       V₂  =  P₁ V₁ T₂ / P₂ T₁

Putting Values,

                       V₂  = (1170 mmHg × 915 mL × 250 K) ÷ (842 mmHg × 297 K)

                       V₂  =  1070 mL or 1.07 L
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3 years ago
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UkoKoshka [18]

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