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masha68 [24]
3 years ago
7

A metallic circular plate with radius r is fixed to a tabletop. An identical circular plate supported from above by a cable is f

ixed in place a distance dd above the first plate. Assume that dd is much smaller than r. The two plates are attached by wires to a battery that supplies voltage V.What is the tension in the cable? Neglect the weight of the plate.Express your answer in terms of the variables d, r, V, and constants ϵ0, pi.F=

Physics
1 answer:
Vinil7 [7]3 years ago
7 0

Answer:

Solution is given in the attachments,below.

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2m/s^2, this is because F=ma, meaning a is also equal to F/m. The car applies 1500N in one direction and outside sources apply a total of -500N, meaning the 500kg car is moving forward with a total of 1000N of force. Taking the total 1000N and dividing it by 500kg gives you and acceleration of 2m/s^2. Hope this helps!
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2 years ago
A 10-foot ladder is leaning straight up against a wall when a person begins pulling the base of the ladder away from the wall at
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Answer:

y = 4.36

Explanation:

Let the height of the ladder be L

L = 10

Also:

  • Let x = distance\ from\ the\ base\ of\ the\ ladder
  • Let y = height\ of\ the\ base\ of\ the\ ladder

When the ladder leans against the wall, it forms a triangle and the length of the ladder forms the hypotenuse.

So, we have:

L^2 = x^2 + y^2 --- Pythagoras Theorem

When the base is 9ft from the wall, this means that:

x = 9

Substitute 9 for x and 10 for L in L^2 = x^2 + y^2

10^2 = 9^2 + y^2

100 = 81 + y^2

Make y^2 the subject

y^2 = 100 - 81

y^2 = 19

Make y the subject

y = \sqrt{19

y = 4.36

<em>Hence, the true distance at that point is approximately 4.36ft</em>

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3 years ago
If a ball is tossed straight up into the air, at what position is its potential energy the greatest? Question 2 options: a) when
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Q1: At the highest point
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A force of attraction would exist between
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Answer:

D. two positively charged objects

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According to Newton’s law of universal gravitation, which statement is true?
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Option (a) is correct.

Falling objects accelerate as they approach the ground.This is because of the force of gravity acting on the falling objects. so the velocity of these objects increases continuously as they approach the ground. the acceleration acting on the falling objects is a constant ( close to the surface of earth) and is called as acceleration due to gravity denoted by g. value of g=9.8 m/s².

4 0
3 years ago
Read 2 more answers
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