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Soloha48 [4]
4 years ago
15

when a skydiver jumps out of a plane, the speed at which he or she falls continues to increase. what force is responsible for th

is increase in speed? URGENT
Physics
1 answer:
bulgar [2K]4 years ago
4 0
Gravity is pulling down the skydiver. The answer is gravity. HOPE I HELPED! :)
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Three forces act on an object. Two of the forces have the magnitudes 56 N and 27 N, and make angles 53° and 156°, respectively,
Ludmilka [50]

Answer:

Explanation:

Given

Two forces F_1 and F_2 at an angle of \theta _1  \theta _2

F_1=56\ N

F_2=27\ N

\theta _1=53^{\circ}

\theta _2=156^{\circ}

As resultant force is zero therefore horizontal component as well as vertical component of force is zero

\sum F_x=F_1\cos \theta _1+F_2\cos \theta _2+F_3\cos \theta _3

\sum F_x=56\cos 53+27\cos 156+F_3\cos \theta

F_3\cos \theta_3=-9.035\ N----1

\sum F_y=F_1\sin \theta _1+F_2\sin \theta _2+F_3\sin \theta _3

F_3\sin \theta _3=55.704\ N----2

squaring and adding 1 and 2

F_3^2(\cos ^2\theta _3+\sin^2\theta _3)=86.583+3102.93

F_3=56.47\ N

Divide 1 and 2 to get \theta _3

\frac{\sin \theta_3 }{\cos \theta_3 }=\frac{-55.704}{9.305}

\tan \theta_3=-6.16

\theta _3=180-80.78

\theta _3=99.22^{\circ}

 

6 0
3 years ago
A basketball player jumps 76cm to get a rebound. How much time does he spend in the top 15cm of the jump (ascent and descent)?
vesna_86 [32]

Answer:

The time for final 15 cm of the jump equals 0.1423 seconds.

Explanation:

The initial velocity required by the basketball player to be able to jump 76 cm can be found using the third equation of kinematics as

v^2=u^2+2as

where

'v' is the final velocity of the player

'u' is the initial velocity of the player

'a' is acceleration due to gravity

's' is the height the player jumps

Since the final velocity at the maximum height should be 0 thus applying the values in the above equation we get

0^2=u^2-2\times 9.81\times 0.76\\\\\therefore u=\sqrt{2\times 9.81\times 0.76}=3.86m/s

Now the veocity of the palyer after he cover'sthe initial 61 cm of his journey can be similarly found as

v^{2}=3.86^2-2\times 9.81\times 0.66\\\\\therefore v=\sqrt{3.86^2-2\times 9.81\times 0.66}=1.3966m/s

Thus the time for the final 15 cm of the jump can be found by the first equation of kinematics as

v=u+at

where symbols have the usual meaning

Applying the given values we get

t=\frac{v-u}{g}\\\\t=\frac{0-1.3966}{-9.81}=0.1423seconds

4 0
3 years ago
describe in words the shape of the velocity vs. time graph. how is this related to the shape of the position vs. time graph
Finger [1]

Answer:

CAN YOU PLEASE GIVE ME POINTS???

Explanation:

4 0
3 years ago
A scientist collected the following data, which show how the pressure of water vapor changes with temperature.
den301095 [7]

Answer:

Make a graph for better visual representation.

Explanation:

Presenting data like that would require someone to see the increase. The best way would be a graph to be shown, to really show the impact by the line going up in the graph.

4 0
3 years ago
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H-2 + H-3 → He-4 +
Svetach [21]
D)
<span>No. the products include He-4, one neutron, and energy.</span>
6 0
3 years ago
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