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3 years ago

4) list 3 protest rights you have that are protected under the law. How can you protect these rights? George Floyd’s ?

Chemistry

1 answer:

Pavel [41]3 years ago

7 0

Peaceful Protest, Signing Pettitons, contacting mayors/governors and writing emails/sending letters

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How many rings does an alkane have if its formula is c10h16?

stepladder [879]

If it is saturated compound then we can calculate the double bond equivalent which will be equal to the number of rings in the compound

the double bond equivalent can be calculated using following formula

$DBE = (C + 1 -\frac{H}{2} - \frac{X}{2} +\frac{N}{2} )$

Where

H = number of Hydrogen atoms

C = number of carbon atoms

X= number of halogen atoms

N = number of nitrogen atoms

DBE = (10 + 1 - 16 / 2 ) = 3

Hence there are three rings in the compound

3 0

3 years ago

Water, also known as H2O, cannot be separated into hydrogen and oxygen.

Dmitry [639]

Answer:

So, H2O means two atoms of hydrogen mixed with one atom of oxygen. All pure water is the same, two parts hydrogen to one part oxygen. ... Water cannot be separated by any physical means.

Explanation:

Logic and my notes from chem....

6 0

3 years ago

Read 2 more answers

At a wastewater treatment plant, FeCl3(s) is added to remove excess phosphate from the effluent. Assume the following reactions

RoseWind [281]

Answer : The concentration of $Fe^{3+}$ needed is, $2.37\times 10^4M$

Explanation :

First we have to calculate the mole of phosphate.

As we are given that, 1 mg P/L that means, 1 mg of phosphate present in 1 L of solution.

$\text{Moles of phosphate}=\frac{\text{Mass of phosphate}}{\text{Molar mass of phosphate}}$

Molar mass of phosphate = 94.97 g/mole

$\text{Moles of phosphate}=\frac{1mg}{94.97g/mol}=\frac{0.001g}{94.97g/mol}=1.053\times 10^{-5}mol$

Now we have to calculate the concentration of phosphate.

$\text{Concentration of phosphate}=\frac{\text{Moles of phosphate}}{\text{Volume of solution}}$

$\text{Concentration of phosphate}=\frac{1.053\times 10^{-5}mol}{1L}=1.053\times 10^{-5}mol/L$

Now we have to calculate the concentration of $Fe^{3+}$ .

The second equilibrium reaction is,

$FePO_4\rightleftharpoons Fe^{3+}+PO_4^{3-}$

The solubility constant expression for this reaction is:

$K_{sp}=[Fe^{3+}][PO_4^{3-}]$

Given: $K_{sp}=\frac{1}{4}$

$\frac{1}{4}=[Fe^{3+}]\times 1.053\times 10^{-5}mol/L$

$[Fe^{3+}]=2.37\times 10^4M$

Thus, the concentration of $Fe^{3+}$ needed is, $2.37\times 10^4M$

8 0

4 years ago

A particular oral contraceptive contains 0.038 mg of ethinyl estradiol in each pill. The formula of this compound is C20H24O2. H

Ray Of Light [21]

<u>Answer:</u> The number of molecules of ethinyl estradiol present in one pill are $7.71\times 10^{16}$

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of ethinyl estradiol = 0.038 mg = $3.8\times 10^-5}g$ (Conversion factor: 1 g = 1000 mg)

Molar mass of ethinyl estradiol $(C_{20}H_{24}O_2)=[(20\times 12)+(24\times 1)+(2\times 16)]=296g/mol$

Putting values in above equation, we get:

$\text{Moles of ethinyl estradiol}=\frac{3.8\times 10^{-5}g}{296g/mol}=1.28\times 10^{-7}mol$

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of molecules

So, $1.28\times 10^{-7}mol$ of ethinyl estradiol will contain = $(1.28\times 10^{-7}\times 6.022\times 10^{23})=7.71\times 10^{16}$ number of molecules

Hence, the number of molecules of ethinyl estradiol present in one pill are $7.71\times 10^{16}$

5 0

3 years ago

A compound has the name iodine pentafluoride. What kind of bond is present between the atoms? A. O Metallic B Covalent C. Hydrog

8090 [49]

Answer:

IF(subscript 5)

Explanation:

covalent.

3 0

3 years ago