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Rainbow [258]
3 years ago
14

HELPPPP PLSSS I NEED HELP

Physics
1 answer:
mojhsa [17]3 years ago
7 0

Answer:

D. Pearl Harbor

Explanation:

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large cylindrical water tank is mounted on a platform with its central axis vertical. The water level is 3.75 m above the base o
eduard

Answer:

0.0000333 m³/s

Explanation:

using Bernoulli's equation

P1 + 1/2ρv1² + ρh1g = P2 + 1/2ρv2² + ρh2g

P1 = P2 both are atmospheric pressure; they cancel out

1/2ρv1² + ρh1g = 1/2ρv2² + ρh2g divide both side with ρ (rho)

1/2v1² + h1g = 1/2v2² +h2g

collect the like terms

h1g - h2g = 1/2v2² + 1/2v1²

multiply both side by 2 and take g out from the left equation

2g(h1 - h2) = v2² + v1² where v1 is approximately 0 assuming the surface of the tank is large

v2² = 2g(h1 - h2)

take square root of both sides

v2 = √2g(h1 - h2)

h1 = 3.75 + 6.5 = 10.25

h2 = 6.5

v2 = √2g(h1 - h2) = √ (2×9.81× (10.25 - 6.5)) = 8.6 m/s

Volume in m³/s = A × v where A is the area of the hole  and the radius of the hole = 2.22 mm / 2 (where 2.22 mm is the diameter of the hole) = 1.11 mm and  1.11mm / 1000 to convert it to meters

Area of the hole ( assuming it is a circle) = πr² = 3.142× (1.11/1000)²

Area = 0.00000387 m²

Volume in M³/s = 0.00000387 × 8.6 = 0.0000333 m³/s

8 0
3 years ago
A thin, metallic spherical shell of radius 0.227 m has a total charge of 6.03 × 10 − 6 C placed on it.
KATRIN_1 [288]

Answer:

Explanation:

Given

radius r=0.227 m

Charge on surface Q=6.03\times 10^{-6} C

Point Charge inside sphere q=1.15\times 10^{-6} C

Electric Field at r=0.735 m

Treating Surface charge as Point charge and applying Gauss law

E_{total}A=\frac{q_{enclosed}}{\epsilon _0}

where A=surface area up to distance r

E_{total}=\frac{Q+q}{4\pi r^2}

E_{total}=\frac{6.03\times 10^{-6}+1.15\times 10^{-6}}{4\pi (0.735)^2\times 8.85\times 10^{-12}}

E_{total}=1.194\times 10^{5} N/C

3 0
4 years ago
I have four questions.
Inga [223]

Answer:

The potential energy of the ball is 784 joules. And the kinetic energy of it is 392 while falling halfway down.

Explanation:

PE = mass (2kg) * Gravitational acceleration (9.8 m/s^2)* height (40 meters)

KE = 1/2 mass (1 kg) * velocity^2 (19.8)

7 0
4 years ago
Read 2 more answers
5. A man in a car is listening to the radio. The radio station is broadcasting at a frequency of 85 MHz from two radio transmitt
nasty-shy [4]

Answer:

Speed = 0.00392 m/s

Explanation:

Solution:

Frequency of the radio = 85 MHz

If we have the frequency, we can calculate the wavelength of the radio wave.

As we know,

Frequency = speed of light/wavelength

wavelength = c/f

c = speed of light = 3 x 10^{8} m/s

So,

Wavelength =  3 x 10^{8} m/s / 85 x 10^{6} Hz

Wavelength = 3.5294 m

Man gets disturbed reception at t = 15 min

t = 15 x 60 = 900 s

t = 900 s

Speed = distance/time

Here, distance is wavelength. So,

Speed =  3.5294 m / 900 s

Speed = 0.00392 m/s

Hence, the man's car is going with speed of 0.00392 m/s

3 0
3 years ago
What is the change all living things undergo as the grow
Vladimir [108]
All of the change that living things undergo as they grow is called development. That is the name when the changes are within a single unit and over a period of time as short as a lifetime. When the change occurs over thousands of years then it's called evolution.
6 0
4 years ago
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