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almond37 [142]
3 years ago
5

Two uniformly charged conducting plates are parallel to each other. They each have area A. Plate #1 has a positive charge Q whil

e plate #2 has a charge −2 Q. Find the magnitude of the electric field at a point P in the gap. Assume that the separation between the plates is very small compared to the dimensions of the plates.
Engineering
1 answer:
Karo-lina-s [1.5K]3 years ago
5 0

Answer:

E = \frac{3Q}{2A\epsilon_0}

Explanation:

By Gauss Law for electric field:

E = \frac{\sigma}{2\epsilon_0}

Where \sigma is the charge density Q/A. Since we have 2 parallel  plates with different charge, the electric field at point P in the gap would be the sum of 2 field

E = E_1 + E_2

E = \frac{Q}{2A\epsilon_0} + \frac{2Q}{2A\epsilon_0}

E = \frac{3Q}{2A\epsilon_0}

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