The range will be all ur y values...just as the domain is all the x values

so ur range is {5,6 }...notice that even though they repeat, u only have to list them once

3 0

3 years ago

Read 2 more answers

Need help please help me if you know it

scoundrel [369]

Answer:

I believe it's C... Not sure though...

7 0

2 years ago

the vertices of PQR are P(-5,1), Q(-4,6), and R(-2,3), graph P"Q"R" after a composition of the transformations in the order they

horsena [70]

SOLUTION

We are told to translate; (x, y) to (x -8, y). This means we have to add - 8 to each value of x in P(-5,1), Q(-4,6), and R(-2,3).

In P(-5,1), x = -5 and y = 1

In Q(-4,6), x = -4 and y = 6 and

In R(-2,3), x = -2 and y = 3

$\begin{gathered} P(-5,\text{ 1) translates to (-5 -8, 1) }\rightarrow P^i(-13,\text{ 1)} \\ Q(-4,\text{ 6) translates to (-4 -8, 6) }\rightarrow Q^i(-12,\text{ 6)} \\ R(-2,\text{ 3) translates to (-2 -8, 3) }\rightarrow R^i(-10,\text{ 3)} \end{gathered}$

For the dilation centered at the origin k =2, simply multiply the value of k, which is 2 into the translations.

$\begin{gathered} At\text{ K = 2, }P^i(-13,\text{ 1) }\rightarrow\text{ }2(-13,\text{ 1) }\rightarrow\text{ }P^{ii}(-26,\text{ 2)} \\ Q^i(-12,\text{ 6) }\rightarrow\text{ }2(-12,\text{ 6) }\rightarrow\text{ Q}^{ii}(-24,\text{ 12)} \\ R^i(-10,\text{ 3) }\rightarrow\text{ }2(-10,\text{ 3) }\rightarrow\text{ R}^{ii}(-20,\text{ 6)} \end{gathered}$

5 0

1 year ago

The length of the box is 2x - 2 and the width is x - 5. Find the perimeter. (HINT: p= 2L + 2W) Choose one.

trasher [3.6K]

Answer:

Option D: 6x-14 is the correct answer.

Step-by-step explanation:

Given that:

Length of the box = L = 2x-2

Width of the box = W = x-5

Perimeter is defined by the sum of length of all sides of the box.

Perimeter of the box = P = 2L + 2W

Perimeter of box = 2(2x-2) + 2(x-5)

Perimeter = 4x-4+2x-10

Perimeter = 6x-14

The perimeter of the box is 6x-14.

Hence,

Option D: 6x-14 is the correct answer.

6 0

3 years ago