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Fantom [35]
3 years ago
5

Single and double replacement

Chemistry
1 answer:
MrMuchimi3 years ago
3 0

Answer:

Explanation:

A single replacement or single displacement reaction is a reaction in which one substance replaces another.

            A  +   BC →   AC + B

The replacement of an ion in solution by a metal higher in the activity series is a special example of this reaction type.

The relative positions of the elements in the activity series provides the driving force for single displacement reactions.

A double replacement reaction is one in which there is an actual exchange of partners between reacting species. This reaction is more common between ionic substances;

              AB + CD → AC + BD

Such reactions are usually driven by;

  • formation of precipitation
  • formation of water and a gaseous product
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True or false: atoms are electrically neutral; that is they do not have a charge.
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Identify the products in the reaction HCI + NaOH → NaCl + H20.
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The addition of 0.242 L of 1.92 M KCl to a solution containing Ag+ and Pb2+ ions is just enough to precipitate all of the ions a
kolezko [41]

Answer:

Mass PbCl₂ = 50.24g

Mass AgCl = 14.84g

Explanation:

The addition of Cl⁻ ions from the KCl solution results in the precipitation of AgCl and PbCl₂ as follows:

Ag⁺ + Cl⁻ → AgCl(s)

Pb²⁺ + 2Cl⁻ → PbCl₂(s)

If we define X as mass of PbCl₂, moles of Cl⁻ from PbCl₂ are:

Xg × (1mol PbCl₂/ 278.1g) × (2moles Cl⁻ / 1 mole PbCl₂) = <em>0.00719X moles of Cl⁻ from PbCl₂</em>

<em />

And mass of AgCl will be 65.08g-X. Moles of Cl⁻ from AgCl is:

(65.08g-Xg) × (1mol AgCl/ 143.32g) × (1mole Cl⁻ / 1 mole AgCl) = <em>0.45409 - 0.00698X moles of Cl⁻ from AgCl</em>

<em />

Moles of Cl⁻ that were added in the KCl solution are:

0.242L × (1.92mol KCl / L) × (1mole Cl⁻ / 1 mole KCl) = 0.46464 moles of Cl⁻ added.

<em />

Moles Cl⁻(AgCl) + Moles Cl⁻(PbCl₂) = Moles Cl⁻(added)

0.45409 - 0.00698X moles + (0.00719X moles) = 0.46464 moles

0.45409 + 0.00021X = 0.46464

0.00021X = 0.01055

X = 0.01055 / 0.00021

X = 50.24g

As X = Mass PbCl₂

<h3>Mass PbCl₂ = 50.24g</h3>

And mass of AgCl = 65.08 - 50.24

<h3>Mass AgCl = 14.84g</h3>

6 0
4 years ago
Which units of pressure are needed if you are going to use 0.0821 as your ideal
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