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s2008m [1.1K]
2 years ago
7

Ben walks 500 meters from his house to the corner store. He then walks back toward his house but stops to talk to a neighbor whe

n he is 200 meters from the corner store. If it takes Ben 910 seconds from the time he leaves his house until he stops to talk to his neighbor, what is his average velocity? (Round your answer to the nearest tenth of a meter per second.)
Chemistry
1 answer:
Arada [10]2 years ago
7 0

Answer:

Average velocity = 0.3 m/s.

Explanation:

Given data:

Total distance from house to store = 500 m

Distance he traveled from store and stop before reached to house = 200 m  

Total time taken = 910 sec

Average velocity = ?

Solution:

Formula:

Average velocity = displacement / time

Displacement = distance from start - end point

Displacement = 500 m - 200 m = 300 m

Average velocity = 300 m/ 910 s

Average velocity = 0.33 m/s

Average velocity = 0.3 m/s.

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<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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  1. [DA] Set up:                                                                                                     \displaystyle 1.51 \cdot 10^{26} \ atoms \ Xe(\frac{1 \ mol \ Xe}{6.022 \cdot 10^{23} \ atoms \ Xe})
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