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allsm [11]
3 years ago
12

A drinking water supply is suspected of being contaminated with lead. Samples of water aspirated directly into an air-acetylene

flame gave an absorbance of 0.68 at 283.3nm. Standard solutions containing 0.5 and 1.0 ppm were found to exhibit absorbances of 0.43 and 0.86 respectively. Assuming the Beer-Lambert law is obeyed calculate the concentration of lead within the water sample. A. 79. Oppm B. 0.79ppm C. 0.43ppm D. 0.96ppm E. 0.92ppm noeullib noilgoeps noods Whaooah
Chemistry
1 answer:
kifflom [539]3 years ago
3 0

Answer:

B. 0.79ppm

Explanation:

According to the Beer-Lambert law, there is a linear relationship between the absorbance (A) of an analyte and its concentration (c). We can represent it through the following expression.

A = k . c

where

k is a proportionality constant, and the slope of the equation.

Let's consider the ordered-pairs (0.5 ppm, 0.43) and (1.0 ppm, 0.86). The slope is:

k = ΔA / Δc = 0.86 - 0.43 / 1.0 ppm - 0.5 ppm = 0.86 ppm⁻¹

When A = 0.68

0.68 = 0.86 ppm⁻¹ c

c = 0.79 ppm

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4 years ago
LICUICY NICULUM
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Answer:

Missing component

Cl₂

H₂O

Explanation:

Reaction given:

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Solution:

Reaction 1

             ? + 2NaBr -----→ 2NaCl + Br

if we look at the reactants and products there is one element is in product side but not shown in the reactant side.

In products there are following atoms

Na (Sodium)

Cl (Chlorine)

Br (Bromine)

In Reactant there are following atoms

Na (Sodium)

Br (Bromine)

So only Chlorine is missing in the reactant side.

if we put chlorine in the reactant then this reaction will be complete

        Cl + 2 NaBr -----→ 2NaCl + Br

So chlorine react with water and give sodium chloride and bromine molecule, this is a single displacement reaction and chlorine replace bromine in the above reaction

Now balance the equation

          Cl₂ + 2 NaBr -----→ 2NaCl + Br₂

So, the missing component is

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____________

Reaction 2

                Mg + ? ---------→ MgO + H₂

if we look at the reactants and products there are two element in product side but not shown in the reactant side.

In products there are following atoms

Mg (Magnesium)

O (Oxygen)

H (Hydrogen)

In Reactant there is only one following atom

Mg (Magnesium)

So Oxygen and Hydrogen is missing in the reactant side.

if we put water molecule (H₂O) in the reactant then this reaction will be complete

          Mg + H₂O ---------→ MgO + H₂

in this reaction magnesium (Mg) react with water (H₂O) and give magnesium oxide and hydrogen gas.

So, the missing component is

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3 0
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Hope this helps!
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Answer: i think that it was 800 mg

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