Answer:
The atomic number of the isotope is reduced by 2 and atomic mass is reduced by 4.
Explanation:
Alpha particle is doubly ionized helium atom. The atomic mass of helium atom is 4 u and atomic number of helium atom is 2. The emission of alpha particle means doubly ionized helium atom will be released from the isotope.
Hence, the emission of the alpha particle will decrease the atomic mass by 4 and atomic number by 2.
Hence, option(a) is correct
Answer: The density because it stays the same with any same liquids or solids or gas with whatever amount of it is added. It only changes if the matter of state is different or there is any environmental change.
It’s is c, if you oook it’s the only clear answer
Answer:
Wavelength, λ = 6.7 x 10^-11 m
Explanation:
Frequency and wavelength are inversely proportional to each other.
In this problem;
f = 4.5 x 10^18 Hz
wavelength, λ = ?
Speed of light, c = 3 x 108 m/s.
These variables are related by the following equation;
c = λ * f
Making λ subject of focus, we have;
λ = c / f
λ = 3 x 10^8 / 4.5 x 10^18
λ = 0.67 x 10^-10
λ = 6.7 x 10^-11 m
