Answer:
bts biot bts biot jungkukkk
 
jungkukkkbiot
Explanation:
bts biot bts biot jungkukkk
 
jungkukkkbiot
 
        
             
        
        
        
Answer: Let us use the pickled file - DeckOfCardsList.dat. 
Explanation: So that our possible outcome becomes
7♥, A♦, Q♠, 4♣, 8♠, 8♥, K♠, 2♦, 10♦, 9♦, K♥, Q♦, Q♣
HPC (High Point Count) = 16  
 
        
             
        
        
        
All of the above. Answer.
        
             
        
        
        
Answer: 
B A and C
Explanation:
Given:
Specimen         σ σ
                      σ
A                       +450                      -150
B                       +300                      -300
C                       +500                      -200
Solution:
Compute the mean stress
σ =  (σ
 =  (σ +  σ
  +  σ )/2
)/2
σ =  (450 + (-150)) / 2
 =  (450 + (-150)) / 2
        =  (450 - 150) / 2  
        = 300/2
σ = 150 MPa
 = 150 MPa
 
σ = (300 + (-300))/2
  = (300 + (-300))/2
         = (300 - 300) / 2
         = 0/2  
σ = 0 MPa
  = 0 MPa
   
σ = (500 + (-200))/2
  = (500 + (-200))/2
         = (500 - 200) / 2
         = 300/2
σ = 150 MPa
  = 150 MPa  
Compute stress amplitude: 
σ =  (σ
 =  (σ -  σ
  -  σ )/2
)/2     
σ =  (450 - (-150)) / 2
 =  (450 - (-150)) / 2
        =  (450 + 150) / 2 
        = 600/2
σ = 300 MPa
 = 300 MPa
σ =  (300- (-300)) / 2
 =  (300- (-300)) / 2
        =  (300 + 300) / 2
        = 600/2
σ = 300 MPa
  = 300 MPa
σ = (500 - (-200))/2
  = (500 - (-200))/2
         = (500 + 200) / 2
         = 700 / 2
σ = 350 MPa
   = 350 MPa 
From the above results it is concluded that the longest  fatigue lifetime is of specimen B because it has the minimum mean stress.
Next, the specimen A has the fatigue lifetime which is shorter than B but longer than specimen C.
In the last comes specimen C which has the shortest fatigue lifetime because it has the higher mean stress and highest stress amplitude.