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Serjik [45]
3 years ago
11

A small car and an SUV are at a stoplight. The car has amass equal to half that of the SUV, and the SUV's engine canproduce a ma

ximum force equal to twice that of the car. Whenthe light turns green, both drivers floor it at the sametime. Which vehicle pulls ahead of the other vehicle after afew seconds?
a) It is a tie.
b) The SUV
c) The car
Physics
1 answer:
Hatshy [7]3 years ago
5 0

Answer:a) It is a tie

Explanation:

Given

mass of car is half of SUV

if mass of SUV is 2m so the mass of car is m

SUV can produce twice the force of car i.e. 2 F

so acceleration experienced by SUV

a_{SUV}=\frac{2F}{2m}

a_{SUV}=\frac{F}{m}

acceleration of Car

a_{car}=\frac{F}{m}

both start with zero initial velocity therefore after few second they will be having same velocity and share same position.

                                 

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Answer:

1 astronomical unit, or AU, is the average distance from the Earth to the Sun; that's about 150 million km. So, Neptune's average distance from the Sun is 30.1 AU. Its perihelion is 29.8 AU, and it's aphelion is 30.4 AU.

Short Answer: it is 29

Explanation:

sorry if its wrong

3 0
3 years ago
supose you have two wires of equal length made from same material. how is it possible for the wires to have different resistance
Ivenika [448]
I'm not sure but I had this question on a benchmark I think its the density of the wire  you need to  find the density or the mass I'm not sure but i do remember this question 
6 0
2 years ago
A skier leaves the horizontal end of a ramp with a velocity of 31.0 m/s and lands 156.3 m from the base of a ramp how high is th
BartSMP [9]

<u>Answer:</u>

The height of ramp = 124.694 m

<u>Explanation:</u>

Using second equation of motion,

s = ut + \frac{1}{2}at^2

From the question,

u = 31 m/s; s = 156.3 m, a=0

substituting values

156.3 = 31\times t + 0

t = \frac{156.3}{31 }

= 5.042 s

Similary, for the case of landing

t = 5.042 s; initial velocity, u =0

acceleration = acceleration due to gravity, g = 9.81 m/s^2

Substituting in h = ut + \frac{1}{2}gt^2

h = 0 + \frac{1}{2} \times 9.81 \times (5.042)^2

h = 124.694 m

So height of ramp = 124.694 m

3 0
3 years ago
Two separate masses on two separate springs undergo simple harmonic motion indefinitely (the surface is frictionless). In CASE 1
Artemon [7]

Answer:

\frac{F_1}{F_2} =\frac{1}{2}

Explanation:

Assuming the we have to find ratio maximum forces on the mass in each case

we know that in a spring mass system

F= Kx

K= spring constant

x= spring displacement

Case 1:

F_1=2k\times d

case 2:

F_2=2k\times 2d

therefore, \frac{F_1}{F_2} = \frac{2K\times d}{2K\times 2d}

\frac{F_1}{F_2} =\frac{1}{2}

4 0
3 years ago
If we decrease the distance an object moves we will
Scrat [10]
Decrease the amount of work done.
4 0
3 years ago
Read 2 more answers
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