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RideAnS [48]
2 years ago
10

Ocean breezes are due to which method of heat transfer?

Physics
2 answers:
Ber [7]2 years ago
8 0
Ocean breezes are due to the convection method of heat transfer
zavuch27 [327]2 years ago
5 0

Answer: Ocean breezes are due to convection method of heat transfer.

Explanation:

Convection: It is a process in which there is an actual movement of heat particle. It is process of the heat transfer.

In Ocean breeze, air moves from ocean towards the land. This is due to the difference in the temperature. Water tends to heat up. It cools off more slowly than the land.

Ocean breezes occurs when air above the ocean is cooler than the land.

Therefore, ocean breezes are due to convection method of heat transfer.

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3 years ago
An engineering firm is designing a ski lift. The wire rope needs to travel with a linear velocity of 2.0 meters per second, and
Mazyrski [523]

Answer:

The diameter of the bull-wheel is 3.82

Explanation:

Given that,

Velocity = 2.0 m/s

Angular velocity = 10 rev/m

\omega=10\times\dfrac{2\pi}{60}

\omega=1.0472\ rad/s

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Which phenomenon would cease to exist in the absence of this axial tilt?
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Does the eruption in the video constitute a pyroclastic flow
densk [106]

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7 0
3 years ago
You release a block from the top of a long, slippery inclined plane of length l that makes an angle θ with the horizontal. The m
Alecsey [184]

Answer:

UG (x) = m*g*x*sin(Q)

Vx,f (x)= sqrt (2*g*x*sin(Q))

Explanation:

Given:

- The length of the friction less surface L

- The angle Q is made with horizontal

- UG ( x = L ) = 0

- UK ( x = 0) = 0

Find:

derive an expression for the potential energy of the block-Earth system as a function of x.

determine the speed of the block at the bottom of the incline.

Solution:

- We know that the gravitational potential of an object relative to datum is given by:

                                   UG = m*g*y

Where,

m is the mass of the object

g is the gravitational acceleration constant

y is the vertical distance from datum to the current position.

- We will consider a right angle triangle with hypotenuse x and angle Q with the base and y as the height. The relation between each variable can be given according to Pythagoras theorem as follows:

                                      y = x*sin(Q)

- Substitute the above relationship in the expression for UG as follows:

                                      UG = m*g*x*sin(Q)

- To formulate an expression of velocity at the bottom we can use an energy balance or law of conservation of energy on the block:

                                      UG = UK

- Where UK is kinetic energy given by:

                                      UK = 0.5*m*Vx,f^2

Where Vx,f is the final velocity of the object @ x:

                                     m*g*x*sin(Q) = 0.5*m*Vx,f^2

-Simplify and solve for Vx,f:

                                    Vx,f^2 = 2*g*x*sin(Q)

Hence, Velocity is given by:

                                     Vx,f = sqrt (2*g*x*sin(Q))

8 0
2 years ago
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