Physics/Math
1 answer:
You might be interested in
Answer:
The correct option is d: T₁ > T₂ > T₃.
Explanation:
Let's evaluate each tension.
<u>Case T₃.</u>
For the system to be in equilibrium, the algebraic sum of the tension force (T) and the weight (W) must be equal to zero. The minus sign of W is because it is in the opposite direction of T.
Since W₃ = mg, where <em>m</em> is for mass and <em>g</em> is for the acceleration due to gravity, we have:
(1) <u>Case T₂.</u>
(2)
By entering W₂ = 2mg and equation (1) into eq (2) we have:
<u>Case T₁.</u>
(3)
Knowing that W₁ = 3mg and T₂ = 3mg, eq (3) is:
Therefore, the correct option is d: T₁ > T₂ > T₃.
I hope it helps you!
In a real system of levers, wheel or pulleys, the AMA (actual mechanical advantage) is less than the IMA (ideal mechanical advantage) because of the presence of friction.
In fact, the IMA and the AMA of a machine are defined as the ratio between the output force (the load) and the input force (the effort):
however, the difference is that the IMA does not take into account the presence of frictions, while the AMA does. As a result, the output force in the AMA is less than the output force in the IMA (because some energy is dissipated due to friction), and the AMA is less than the IMA.
In fact, the IMA and the AMA of a machine are defined as the ratio between the output force (the load) and the input force (the effort):
however, the difference is that the IMA does not take into account the presence of frictions, while the AMA does. As a result, the output force in the AMA is less than the output force in the IMA (because some energy is dissipated due to friction), and the AMA is less than the IMA.