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3 years ago

When a solid compound dissolves in water,

1 answer:

6 0

The answer is d. Each of its particles becomes surrounded by water molecules.

Notice that when you dissolve a solid compound in the water, it is no longer visible in or eyes, it mixes in the water, it is because it is being divided into smaller particles and each particles were surrounded by the water molecules.

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Barney walks at a velocity of 1.7 meters/second on an inclined plane, which has an angle of 18.5° with the ground. What is the h

Viktor [21]

The velocities and the speed build a triangle, where the 1.7 m/s are the hypotenuse and the x-velocity and y-velocity are the other sides.

So the x-velocity is: speed*cos(angle) 

now plug in 
x=1.7 m/s * cos(18.5)=1.597 m/s

3 0

3 years ago

A length of copper wire carries a current of 14 A, uniformly distributed through its cross section. The wire diameter is 2.5 mm,

gavmur [86]

Answer:

a. ρ $_\beta=1.996J/m^3$

b. $U_E=9.445x10^{-15} J/m^3$

Explanation:

a. To find the density of magnetic field given use the gauss law and the equation:

$i=14A$ , $d=2.5mm$ , $R=3.3$ Ω, $l=1 km$ , $E_o=8.85x10^{-12}F/m$ , $u_o=4*x10^{-7}H/m$

ρ $_\beta=\frac{\beta^2}{2*u_o}$

ρ $_\beta=\frac{1}{2*u_o}*(\frac{u_o*i^2}{2\pi *r})^2$

ρ $_\beta=\frac{u_o*i^2}{8\pi*r}=\frac{4\pi *10^{-7}H/m*(14A)^2}{8\pi*(1.25x10^{-3}m)^2}$

ρ $_\beta=1.996J/m^3$

b. The electric field can be find using the equation:

$U_E=\frac{1}{2}*E_o*E^2$

$E=(\frac{i*R}{l})^2$

$U_E=\frac{1}{2}*8.85x10^{-12}*(\frac{14A*3.3}{1000m})^2$

$U_E=9.445x10^{-15} J/m^3$

4 0

3 years ago

What does the formula "F=m xa" mean?

strojnjashka [21]

Answer:

Force = Mass x Acceleration

Explanation:

5 0

3 years ago

What type of planet is Venus?

mafiozo [28]

Venus would be an inner planet!
x

7 0

3 years ago

Read 2 more answers

A circuit contains a single 270-pf capacitor hooked across a battery. it is desired to store four times as much energy in a comb

yan [13]

The energy stored by a system of capacitors is given by
$U= \frac{1}{2}C_{eq} V^2$
where Ceq is the equivalent capacitance of the system, and V is the voltage applied.

In the formula, we can see there is a direct proportionality between U and C. This means that if we want to increase the energy stored by 4 times, we have to increase C by 4 times, if we keep the same voltage.

Calling $C_1 = 270 pF$ the capacitance of the original capacitor, we can solve the problem by asking that, adding a new capacitor with $C_x$ , the new equivalent capacitance of the system $C_{eq}$ must be equal to $4C_1$ . If we add the new capacitance X in parallel, the equivalent capacitance of the new system is the sum of the two capacitance
$C_{eq} = C_1 + C_x$
and since Ceq must be equal to 4 C1, we can write
$C_1+C_x = 4C_1$
from which we find
$C_x=3C_1=3 \cdot 270 pF=810 pF$

5 0

3 years ago