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3 years ago

Which is the best example of Newton’s SECOND law of motion:

Physics

1 answer:

Olin [163]3 years ago

6 0

Which is the best example of Newton’s SECOND law of motion:

C.) A baseball player hits a baseball that is pitched to him. The ball immediately soars back in the direction of the pitcher.

~Hope this answers your question!~

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A 3.5-kg object placed on an inclined plane (angle 30? above the horizontal) is connected by a string going over a pulley to a 1

Blababa [14]

Answer:

a= 0.22 m/s²

Explanation:

Given that

M = 3.5 kg

θ = 30°

m = 1 kg

μ= 0.3

The force due to gravity

F₁= M g sinθ

F₁=3.5 x 10 x sin 30

F₁= 17.5 N

F₂ = m g

F₂ = 1 x 10 = 10 N

The maximum value of the friction force on the incline plane

Fr = μ M g cosθ

Fr = 0.3 x 2.5 x 10 cos30°

Fr= 6.49 N

Lets take acceleration of the system is a m/s²

F₁ - F₂ - Fr = (M+m) a

17.5 - 10 - 6.49 = (3.5+1)a

a= 0.22 m/s²

7 0

3 years ago

A backpack weighs 8.2 newtons and has a mass of 5kg on the moon. What is the strength of the gravity on the moon?

Pavel [41]

Weight is equivalent to the product of the mass of an object and the strength of the gravitational field.

Using:
F = ma

a = 8.2 / 5
a = 1.64 N/kg

The gravitational field strength is equivalent to 1.64 N/kg.

7 0

3 years ago

WILL MAKE BRAINLYEST!!!!!! PLZ HELP

mylen [45]

Answer:

Explanation:

4 0

3 years ago

You have a string with a mass of 0.0127 kg. You stretch the string with a force of 9.33 N, giving it a length of 1.93 m. Then, y

melomori [17]

Answer:

wavelength = 0.968 m

frequency = 39.02 Hz

Explanation:

given data

mass = 0.0127 kg

force = 9.33 N

length = 1.93 m

to find out

wavelength and Frequency

solution

we know here linear density that is

linear density = $\frac{mass}{length}$ .........1

linear density = $\frac{0.0127}{1.93}$

linear density = 6.5803 × $10^{-3}$ kg/m

wavelength will be here

wavelength = $\frac{2L}{n}$ ..............2

here n = 4 for forth harmonic

wavelength = $\frac{2*1.93}{4}$

wavelength = 0.968 m

and

frequency will be for 4th normal mode of vibration is

frequency = $\frac{4}{2L} \sqrt{\frac{tension}{linear\ density} }$ ..........3

frequency = $\frac{4}{2*1.93} \sqrt{\frac{9.33}{6.5803*10^{-3}} }$

frequency = 1.036269 × 37.654594

frequency = 39.02 Hz

5 0

3 years ago

It has been suggested that a heat engine could be developed that made use of the fact that the temperature several hundred meter

lesantik [10]

Answer:

efficiency = 5.4%

Explanation:

Efficiency of heat engine is given as

$\eta = \frac{W}{Q_{in}}$

now we will have

$W = Q_1 - Q_2$

so we will have

$\eta = 1 - \frac{Q_2}{Q_1}$

now we know that

$\frac{Q_2}{Q_1} = \frac{T_2}{T_1}$

so we have

$\eta = 1 - \frac{T_2}{T_1}$

$\eta = 1 - \frac{273+6}{273+22}$

$\eta = 0.054$

so efficiency is 5.4%

8 0

3 years ago