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kifflom [539]
3 years ago
13

In a magnetized substance, the domains __________________________ .

Physics
1 answer:
ahrayia [7]3 years ago
5 0
I think the answer you're looking for is -are randomly oriented. if not sorry... i tried.
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A force in the +x-direction with magnitude ????(x) = 18.0 N − (0.530 N/m)x is applied to a 6.00 kg box that is sitting on the ho
fiasKO [112]

Answer:

v_f=8.17\frac{m}{s}

Explanation:

First, we calculate the work done by this force after the box traveled 14 m, which is given by:

W=\int\limits^{x_f}_{x_0} {F(x)} \, dx \\W=\int\limits^{14}_{0} ({18N-0.530\frac{N}{m}x}) \, dx\\W=[(18N)x-(0.530\frac{N}{m})\frac{x^2}{2}]^{14}_{0}\\W=(18N)14m-(0.530\frac{N}{m})\frac{(14m)^2}{2}-(18N)0+(0.530\frac{N}{m})\frac{0^2}{2}\\W=252N\cdot m-52N\cdot m\\W=200N\cdot m

Since we have a frictionless surface, according to the the work–energy principle, the work done by all forces acting on a particle equals the change in the kinetic energy of the particle, that is:

W=\Delta K\\W=K_f-K_i\\W=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}

The box is initially at rest, so v_i=0. Solving for v_f:

v_f=\sqrt{\frac{2W}{m}}\\v_f=\sqrt{\frac{2(200N\cdot m)}{6kg}}\\v_f=\sqrt{66.67\frac{m^2}{s^2}}\\v_f=8.17\frac{m}{s}

5 0
3 years ago
A student drops an object out the window of the top floor of a high-rise dormitory.
seropon [69]

-- The acceleration due to gravity is 32.2 ft/sec² .  That  means that the
speed of a falling object increases by an additional 32.2 ft/sec every second.

-- If dropped from "rest" (zero initial speed), then after falling for 4 seconds,
the object's speed is (4.0) x (32.2) = <em>128.8 ft/sec</em>.

-- 128.8 ft/sec = <em>87.8 miles per hour</em>

Now we can switch over to the metric system, where the acceleration
due to gravity is typically rounded to 9.8 meters/sec² .

-- Distance = (1/2) x (acceleration) x (time)²

       D = (1/2) (9.8) x (4)² =<em>  78.4 meters</em>

-- At 32 floors per 100 meters,  78.4 meters = dropped from the <em>25th floor</em>.


The 5 points are certainly appreciated, but I do wish they were Celsius points.


3 0
3 years ago
Why were the rings of Uranus not observed directly from telescopes on the ground on Earth? How were they discovered?
leonid [27]

Answer:Explained below.

Explanation:

Uranus rings is made up of jet black, coal-like particles in small bands, making them difficult  to perceive from Earth.This indicates that they are probably composed of a mixture of the ice and a dark material. The nature of  material is dismal, but it might be some organic compounds greatly darkened by the charged particle irradiation from the Uranian magnetosphere. Rings were discovered by using a infrared telescope throughout  the occultation of a star as Uranus passed in front of it. The light from the star dimmed many times before it was obstructed by the disk of Uranus and subsequently, showing the presence of various distinct rings.

6 0
3 years ago
Differences between sublimation and condensation
zaharov [31]

The difference between sublimation and condensation is that

Sublimation is used to in a separation technique to separate sublime substance from a mixture while condensation is the

is the process where water vapor becomes liquid

<h3>What is separation technique?</h3>

This technique is used in chemistry to separate two or more constituents from a mixture

In conclusion, sublimation differs from condensation because sublimation is used to in a separation technique to separate sublime substance from a mixture while condensation is the

is the process where water vapor becomes liquid

Learn more about separation technique:

brainly.com/question/10862519

#SPJ1

5 0
2 years ago
The voltage ???? in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance ???? is slowly inc
zimovet [89]

Answer:

The change in current at  R =456 \Omega is  \frac{dI}{dt}  = 7.032 * 10^{-5} A/s

Explanation:

From the question we are told that

    The resistance is R = 465 \Omega

     The current is  I = 0.09A

    The change in voltage with respect to time is \frac{dV}{dt}  = - 0.03 V/s

     The change in resistance with time is  \frac{dR}{dt}  =  0.03 \Omega /s

According to ohm's law

        V =  IR

differentiating with respect to time using chain rule

             \frac{dV}{dt}  =  I \frac{dR}{dt} + R * \frac{dI}{dt}

substituting value  at R = 456

             -0.0327 =  0.09 * 0.03 + 456* \frac{dI}{dt}

              \frac{dI}{dt}  = 7.032 * 10^{-5} A/s

6 0
3 years ago
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