1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NARA [144]
3 years ago
13

The theoretical yield is the amount of product actually produced. a. True b. False

Chemistry
2 answers:
jolli1 [7]3 years ago
6 0

Answer:

a. True

Explanation:

Theoretical yield is the amount of product that could be obtained if a chemical reaction has 100% efficiency.

Hope it helps...

gizmo_the_mogwai [7]3 years ago
5 0
Falseee
It is actually The amount of product measured in grams that you would theoretically produce is every atom of the reactants reacted
You might be interested in
A chemistry graduate student is given 125.mL of a 1.00M benzoic acid HC6H5CO2 solution. Benzoic acid is a weak acid with =Ka×6.3
lubasha [3.4K]

Answer:

53.9 g

Explanation:

When talking about buffers is very common the problem involves the use of the Henderson Hasselbach formula:

pH = pKa + log [A⁻]/[HA]

where  [A⁻] is the concentration of the conjugate base of the weak acid HA, and [HA] is the concentration of the weak acid.

We can calculate pKₐ from the given kₐ ( pKₐ = - log Kₐ ), and from there obtain the ratio  [A⁻]/HA].

Since we know the concentration of HC6H5CO2 and the volume of solution, the moles and mass of KC6H5CO2  can be determined.

So,

4.63 = - log ( 6.3 x 10⁻⁵ ) + log [A⁻]/[HA] = - (-4.20 ) + log [A⁻]/[HA]

⇒ log [A⁻]/[HA]  = 4.63 - 4.20 =  log [A⁻]/[HA]

0.43 = log [A⁻]/[HA]

taking antilogs to both sides of this equation:

10^0.43 =  [A⁻]/[HA] = 2.69

 [A⁻]/ 1.00 M = 2.69 ⇒ [A⁻] = 2.69 M

Molarity is moles per liter of solution, so we can calculate how many moles of  C6H5CO2⁻ the student needs to dissolve  in 125. mL ( 0.125 L ) of a 2.69 M solution:

( 2.69 mol C6H5CO2⁻ / 1L ) x 0.125 L  = 0.34 mol C6H5CO2⁻

The mass will be obtained by multiplying 0.34 mol times molecular weight for KC6H5CO2 ( 160.21 g/mol ):

0.34 mol x 160.21 g/mol = 53.9 g

3 0
3 years ago
QUESTION 7
Lera25 [3.4K]
Answer:
it’s quite simple.
The newton force in a aerodynamic space which could lead to a catastrophic entanglement will be added to the physical quantum molecular structure then subtracted by its opposite, inter dimensional indispensable aerobic activity, then finally multiplied by the sum which was subtracted by the addition to then divide the sum of it all with the solution of the multiplication which would equal to the answer.
4 0
3 years ago
Electrical energy is the energy of__________
Arturiano [62]

Answer:

<h3>electrical energy is the energy of Kinetic energy </h3>

Explanation:

<h3>I hope l helped you.</h3>
6 0
2 years ago
Read 2 more answers
What is a compound
Mariulka [41]

Answer:

B

Explanation:

because sea water taste like Salt

8 0
2 years ago
Read 2 more answers
14. The following are a list of the four parts of John Dalton's atomic theory Indicate which of
Damm [24]

Answer:

1

all matter is made of tiny particles called atom

5 0
2 years ago
Other questions:
  • Calculate 50g 25.0c to 95.000<br>O.897 J / (g.c)​
    12·1 answer
  • What is required to move from one state or phase of matter to the next
    10·1 answer
  • How can I separate gasoline and vegetable oil?
    13·1 answer
  • 1.00mol of oxygen gas has a pressure of 2.50atm at 325K. Use the ideal gas law to determine the volume of the gas.
    8·1 answer
  • Which uses of iron are due to its chemical properties? Select two options.
    7·2 answers
  • What is the concentration , in grams per liter , of a solution containing 6 mEq of calcium chloride ( CaCl2 ) per milliliter ? (
    10·1 answer
  • What are the products in a chemical reaction?
    12·1 answer
  • I need help please help<br>​
    12·1 answer
  • Simplify - Factor a
    15·1 answer
  • Which observation most likely indicates that only a chemical change has taken place
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!