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Andreas93 [3]
3 years ago
8

Wanted to measure the pressure of oxygen gas in a closed container. She measured pressure at four points; at the top, bottom, le

ft, and right sides of the container.
Chemistry
1 answer:
rewona [7]3 years ago
3 0
The question isnt finished
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Solubility of a salt that has a general formula M3X (where M is the cation and X is the anion) is 0.0283 g/L of the solution. Th
egoroff_w [7]

ksp = 7.003 \times  {10}^{ - 16}  {mol}^{4}  {dm}^{ - 12}

6 0
3 years ago
Sodium oxide reacts with water to make sodium hydroxide.
Vlada [557]

Answer:

So the total mass is 50 plus 150 grams the heat capacity 4.18 joules per gram per degree C. And the temperature change is 36 minus 25 and so we can calculate Delta H for the reaction that takes place.

Explanation:

3 0
3 years ago
Answer all questions pls
tekilochka [14]

Answer:

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Explanation:

U dont have to copy and paste this put these are some ideas to use for ur answers

6 0
3 years ago
Potassium chlorate (used in fireworks, flares, and safety matches) forms oxygen and potassium chloride when heated. KClO3(s) → K
Zina [86]

Answer:

10.3 g of oxygen are formed when 26.4 g of potassium chlorate is heated

Explanation:

This is the balanced equation:

2KClO₃(s) → 2KCl(s) + 3O₂(g)

Ratio beteween the salt and oxygen is 2:3

Molar mass of KClO₃ = 122.55 g/m

Let's find out the moles of salt

Mass / Molar mass

26.4 g /122.55 g/m = 0.215 moles

So, this is the final rule of three:

If 2 moles of KClO₃ make 3 moles of oxygen

0.215 moles of KClO₃ make  (0.215  .3) /2 = 0.323 moles of O₂ are produced

Molar mass O₂ = 32 g/m

Moles . molar mass = mass

0.323 m  . 32g/m = 10.3 g

4 0
3 years ago
To test the effectiveness of a gunpowder mixture, 1 gram was exploded under controlled STP conditions, and the reaction chamber
Alekssandra [29.7K]

Answer:

1.3 × 10³ cm³

Explanation:

The gas occupies a volume of V₁ = 310 cm³ under standard temperature and pressure (STP), that is, T₁ = 273.15 K and P₁ = 1.0 atm. In order to find the volume V₂ under different conditions we can use the combined gas law formula.

\frac{P_{1}.V_{1}}{T_{1}} =\frac{P_{2}.V_{2}}{T_{2}} \\V_{2}=\frac{P_{1}.V_{1}.T_{2}}{T_{1}.P_{2}}=\frac{1.0atm\times 310cm^{3} \times 2473K }{273.15K \times 2.1atm} =1.3 \times 10^{3} cm^{3}

7 0
3 years ago
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