The answer is three because within 6 there are 3 groups of 2 within 6.
By evaluating, we will see that for x = 7 h(x) exceeds g(x).
<h3>
For which value of x does h(x) first exceed g(x)?</h3>
We have:
h(x) = 2*(2)^x
g(x) = 22x - 4
Now we can evaluate both function in the different options:
h(5) = 2*(2)^5 = 64
g(5) = 22*5 - 4 = 106
We can see that for x = 5, h(x) does not exceed g(x), let's try the next one.
h(6) = 2*(2)^6 = 128
g(6) = 22*6 - 4 = 128
So, for x = 6 both functions have the same output, then for x = 7 we will see that h(x) exceeds g(x).
The correct option is B.
If you want to learn more about functions:
brainly.com/question/4025726
#SPJ1
Answer:
1. 27
2. 1 and 2 = 17
3. 55
4. 55
5. 70
6. 125
7. 55
8. 95
9. 140
10. 40
11. 65
12. 75
13. 115
14. 27
15. 27
Step-by-step explanation:
12/x
12 divided by x
Hope this helps please mark brainiest answer!
