Let's assume that both He and N₂ have ideal gas behavior.<span>
Then we can use ideal gas law,
PV = nRT
Where, P is the pressure of gas, V is the volume,
n is moles of gas, R is universal gas constant and T is the temperature in
Kelvin.
<span>The </span>P <span>and </span>V <span>are </span>same<span> for the
both gases.</span>
R is a
constant.
The only variables are n and T.
<span>Let's say temperature of </span>He<span> <span>is </span></span>T</span>₁<span> <span>and temperature of </span></span>N₂<span> <span>is </span></span>T₂.<span>
n = m/M<span> where n is
moles, m is mass and M is molar mass.</span>
Molar mass of He is 4 g/mol and molar mass of N₂ is 28 g/mol</span><span>
<span>Since mass (m) of both gases are same,</span>
moles of He = m/4
moles of N₂ = m/28</span><span>
Let's apply the ideal gas equation for both gases.
For He gas,
PV = (m/4)RT₁ </span>(1)<span>
For N</span>₂ gas,<span>
PV = (m/28)RT₂<span> </span></span> (2)<span>
(1) = (2)
</span><span>(m/4)RT₁ =
(m/28)RT₂</span> <span>
T₁/4
= T₂/28</span><span>
T₁ = T₂/7</span><span>
<span> </span>7T</span>₁ = T₂<span>
Hence, the
temperature of N</span>₂<span> gas is higher by 7
times than the temperature of He gas.</span>
Answer:
The volume is 22,710 980(38) litres for the ideal gas
Breaking down that’s why they make land slides
True will end up being the answer
1. Molarity : 0.25 M
2. mol CH₄ = 7.4 moles
mol O₂ = 14.8 moles
<h3>Further explanation</h3>
1.
Given
83.2 g CuCl2 in 2.5 liters of water
Required
the molarity
Solution
Molarity : mol solute per liter of solution(not per liter of solvent)
mol solute = mol CuCl₂
mol CuCl₂ = mass : MW CuCl₂
mol CuCl₂ = 83.2 : 134.45
mol CuCl₂ = 0.619
Molarity(M) = mol : V
Assume density CuCl₂ = 3.39 g/cm³
volume CuCl₂ = 8.32 g : 3.39 g/cm³ = 2.45 cm³=2.45 x 10⁻³ L
With this small volume value of CuCl₂, the volume of the solute is sometimes neglected in calculating molarity
volume of solution = 2.5 L + 2.45 x 10⁻³ L = 2.50245 L
Molarity(M) = mol : V
M = 0.619 : 2.50245 L = 0.247≈0.25
2.
Given
Reaction
The correct balanced reaction:
CH4 + 2O2 → CO2 + 2H2O
7.4 moles CO2
Required
moles of methane (CH4) and oxygen gas (O2)
Solution
From the equation, mol ratio of CO₂ : CH₄ : O₂ = 1 : 1 : 2
mol CH₄ = mol CO₂ = 7.4 moles
mol O₂ = 2 x mol CO₂ = 2 x 7.4 moles = 14.8 moles