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2 years ago

Can someone help me with this

Chemistry

1 answer:

zlopas [31]2 years ago

3 0

Answer:

wow!

5. C

6. B

7. B

8. A

Explanation:

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Identify the solution that contains both the solute and solvent in the solid phase. A) air B) NaCl C) bronze D) salt water

Iteru [2.4K]

Answer:prolly c

Explanation:

5 0

3 years ago

Need asap! Step-by-step pls: Determine the empirical formula: 32.37% Na, 22.58% S, 45.05% O

Ludmilka [50]

1) divide each percentage by the relative atomic mass of the element

2) divide all results by the smallest number

3)multiply by a whole number to get the simplest whole number ratio (if necessary)

that is to say:

Na S O

32.37÷23 22.58÷32 45.05÷16

= 1.407 = 0.7056 = 2.816 (to 4 significant figures)

the smallest number here is 0.7056 so:

1.407÷0.7056 0.7056÷0.7056 2.816÷0.7056

=1.99 approx.2 = 1 3.99 approx. 4

here there is no need to carry out step 3 as ratio obtained is already a simplest whole number ratio

so empirical formula is: Na₂SO₄

8 0

3 years ago

HELP!!! TIMED! THANK YOU!

Bess [88]

Answer:

The answer is A.

Explanation:

8 0

2 years ago

Read 2 more answers

Solid potassium chlorate decomposes upon heating to form

olga55 [171]

Answer:

32.6%

Explanation:

Equation of reaction

2KClO₃ (s) → 2KCl (s) + 3O₂ (g)

Molar mass of 2KClO₃ = 245.2 g/mol ( 122.6 × 2)

Molar volume of Oxygen at s.t.p = 22.4L / mol

since the gas was collected over water,

total pressure = pressure of water vapor + pressure of oxygen gas

0.976 = 0.04184211 atm + pressure of oxygen gas at 30°C

pressure of oxygen = 0.976 - 0.04184211 = 0.9341579 atm = P1

P2 = 1 atm, V1 = 789ml, V2 = unknown, T1 = 303K, T2 = 273k at s.t.p

Using ideal gas equation

$\frac{P1V1}{T1}$ = $\frac{P2V2}{T2}$

V2 = $\frac{P1V1T2}{T1P2}$

V2 = 664.1052 ml

245.2 yielded 67.2 molar volume of oxygen

0.66411 will yield = $\frac{245.2 * 0.66411}{67.2}$ = 2.4232 g

percentage of potassium chlorate in the original mixture = $\frac{2.4232 * 100}{7.44}$ = 32.6%

3 0

3 years ago

Calculate the amount of heat, in kilojoules, required to turn solid ammonia at -78 degrees Celsius to gaseous ammonia at standar

zhuklara [117]

Answer:

132

Explanation:

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3 years ago