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zavuch27 [327]
3 years ago
8

PLEASE HELP! IM BEING TIMES!!!!!!!

Mathematics
1 answer:
Paul [167]3 years ago
6 0

Answer:

Answer is D.

Step-by-step explanation:

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Strong moderate or weak correlation r=-0.91, r=0.82, r=-0.49, r=0.26, r=0.54, r=-0.18
Mariulka [41]

So one key thing to remember here is that the direction of the correlation is irrelevant, that is it does not matter if your correlation is + or - what matters is how close that number is to 1.0.

To help you out here are the ranges of correlation strength

  • 0.70. A strong relationship
  • 0.50. A moderate relationship
  • 0.30. A weak relationship

So to start off with 0.26 and 0.18 are very small correlations so you'd call those weak correlations.

Let me know if you need help doing the other ones? It should be simple enough with the data I gave you :)


6 0
3 years ago
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Can the law of sines be used to solve the triangle
ivanzaharov [21]

Answer:

No

Step-by-step explanation:

No, the law of sines cannot be used to solve the triangle. The triangle shows the measures of two sides and an included angle. To use the law of sines, you need to know the measure of an angle and its opposite side.

Answer On Edg. 2020

8 0
3 years ago
Can someone pls help?
GenaCL600 [577]

Answer: 2

Step-by-step explanation:

Because if u divide 12÷6=2 2×6=12

3 0
3 years ago
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Enter an expression for the perimeter of the given figure. Simplify the expression.
dlinn [17]

Answer:

4x + 28.4 in.

Step-by-step explanation:

perimeter = sum of lengths of sides

perimeter = x + 2 + x + 2 + x + 2 + x + 2 + 10.2 + 10.2

perimeter = 4x + 28.4

3 0
2 years ago
Rewrite \sqrt((1+cos45)/(2)) using a half-angle identity
aleksklad [387]

\stackrel{\textit{Half-Angle Identities}}{cos\left(\cfrac{\theta}{2}\right)=\pm \sqrt{\cfrac{1+cos(\theta)}{2}}} \\\\[-0.35em] ~\dotfill\\\\ \sqrt{\cfrac{1+cos(45^o)}{2}}~~ = ~~cos\left( \cfrac{45^o}{2} \right)\implies \sqrt{\cfrac{1+cos(45^o)}{2}}~~ = ~~cos(22.5^o)

7 0
2 years ago
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