Answer:
I'm pretty sure they either terminate after so many digits (end) or repeat a certain pattern of numbers.
Step-by-step explanation:
The first will look like this: 432.2340
The second would look like this: 324.234234234... ("234" would keep repeating over and over and over. And can be any sequence of #'s)
^Random numbers were used as examples^
Μ = (0×0.026) + (1×0.072) +(2×0.152) + (3×0.303) + (4×0.215) + (5×0.164) + (6×0.066)
μ = 0 + 0.072 + 0.304 + 0.909 + 0.86 + 0.82 + 0.396
μ = 3.361 ≈ 3.4
We need the value of ∑X² to work out the variance
∑X² = (0²×0.026) + (1²×0.072) + (2²×0.152) + (3²×0.303) + (4²×0.215) + (5²×0.164) + (6²×0.066)
∑X² = 0+0.072+0.608+2.727+3.44+4.1+2.376
∑X² = 13.323
Variance = ∑X² - μ²
Variance = 13.323 - (3.4)² = 1.763 ≈ 2
Standard Deviation = √Variance = √1.8 = 1.3416... ≈ 1.4
The correct answer related to the value of mean and standard deviation is the option D
<span>
An employee works an average of 3.4 overtime hours per week with a standard deviation of approximately 1.4 hours.</span>
Answer:
e^2
Step-by-step explanation:
Answer=24.49 I’m not 100% sure but I believe this is the answer :)
Hope it helps
Let <em>a</em> and <em>b</em> be the two numbers. Then
<em>a</em> + <em>b</em> = -4
<em>a b</em> = -2
Solve the second equation for <em>b</em> :
<em>b</em> = -2/<em>a</em>
Substitute this into the first equation:
<em>a</em> - 2/<em>a</em> = -4
Multiply both sides by <em>a</em> :
<em>a</em>² - 2 = -4<em>a</em>
Move 4<em>a</em> to the left side:
<em>a</em>² + 4<em>a</em> - 2 = 0
Use the quadratic formula to solve for <em>a</em> :
<em>a</em> = (-4 ± √(4² - 4(-2))) / 2
<em>a</em> = -2 ± √6
If <em>a</em> = -2 + √6, then
-2 + √6 + <em>b</em> = -4
<em>b</em> = -2 - √6
In the other case, we end up with the same numbers, but <em>a</em> and <em>b</em> are swapped.