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skad [1K]
3 years ago
9

Solve the integral:

20dx" id="TexFormula1" title=" \int \: {e}^{ - {x}^{2} } dx" alt=" \int \: {e}^{ - {x}^{2} } dx" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Sever21 [200]3 years ago
8 0

e^{-x^2} has no antiderivative in terms of elementary functions (polynomials, exponentials, logarithms, trigonometric functions, etc), but there is a special function defined to fit that role called the error function, \mathrm{erf}(x), where

\mathrm{erf}(x)=\displaystyle\frac2{\sqrt\pi}\int_0^xe^{-t^2}\,\mathrm dt

By the fundamental theorem of calculus, we can see that

\dfrac{\mathrm d}{\mathrm dx}\mathrm{erf}(x)=\dfrac2{\sqrt\pi}e^{-x^2}

which means we have

\displaystyle\int e^{-x^2}\,\mathrm dx=\dfrac{\sqrt\pi}2\mathrm{erf}(x)+C

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We're testing the hypothesis that the average boy walks at 18 months of age (H0: p = 18). We assume that the ages at which boys
marusya05 [52]

Answer:

II. This finding is significant for a two-tailed test at .01.

III. This finding is significant for a one-tailed test at .01.

d. II and III only

Step-by-step explanation:

1) Data given and notation    

\bar X=19.2 represent the battery life sample mean    

\sigma=2.5 represent the population standard deviation    

n=25 sample size    

\mu_o =18 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

2) State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean battery life is equal to 18 or not for parta I and II:    

Null hypothesis:\mu = 18    

Alternative hypothesis:\mu \neq 18    

And for part III we have a one tailed test with the following hypothesis:

Null hypothesis:\mu \leq 18    

Alternative hypothesis:\mu > 18  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:    

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

3) Calculate the statistic    

We can replace in formula (1) the info given like this:    

z=\frac{19.2-18}{\frac{2.5}{\sqrt{25}}}=2.4    

4) P-value    

First we need to calculate the degrees of freedom given by:  

df=n-1=25-1=24  

Since is a two tailed test for parts I and II, the p value would be:    

p_v =2*P(t_{(24)}>2.4)=0.0245

And for part III since we have a one right tailed test the p value is:

p_v =P(t_{(24)}>2.4)=0.0122

5) Conclusion    

I. This finding is significant for a two-tailed test at .05.

Since the p_v. We reject the null hypothesis so we don't have a significant result. FALSE

II. This finding is significant for a two-tailed test at .01.

Since the p_v >\alpha. We FAIL to reject the null hypothesis so we have a significant result. TRUE.

III. This finding is significant for a one-tailed test at .01.

Since the p_v >\alpha. We FAIL to reject the null hypothesis so we have a significant result. TRUE.

So then the correct options is:

d. II and III only

6 0
3 years ago
Popcorn kernels pop independently (i.e. unimolecularly). For one brand at constant temperature, 12 kernels pop in 5 seconds when
likoan [24]

Answer:

no of kernels  pop = 4.34

Step-by-step explanation:

given data

kernels pop in 5 second  = 12

kernels are present = 235

solution

we get here kernels are pop at rate of here

kernels are pop at rate = 12  ÷  235  

kernels are pop at rate = 0.051063

and

we get here maximum kernels are remaining that is

maximum kernels remaining = 235 - 140

maximum kernels remaining = 85

so

no of kernels  pop in 5 second will be

no of kernels  pop = 0.051063   × 85

no of kernels  pop = 4.34

7 0
3 years ago
I am stuck on this question of my maths test.
V125BC [204]

Answer:

angle y

58 + 38 + y = 180 (angle sum property)

96 + y = 180

y = 180 - 96

y = 84

angle x

x = 29 (58/2)

(angle subtended by an arc at centre is double the arc at any point on remaining part of centre)

the values of x = 29 and y = 84

6 0
3 years ago
A menu has three meat choices, three vegetable choices and two
Paha777 [63]

Answer:

18 ways

Step-by-step explanation:

The computation of the number of ways that could be choose your dinner as follows:

= 3 meat choices × 3 vegetable choices × 2 desserts

= 18 ways

By multiplying all the three things we can determined the number of ways

8 0
2 years ago
What are the vertical and horizontal asymptotes in this function? <br><br> f(x)=4x-4/x^3 -8
iogann1982 [59]
<span>i dont think i know how to solve this one

</span>
7 0
3 years ago
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