Imagine a small synthetic vesicle made from pure phospholipids enclosing an interior lumen containing 1 mM glucose and 1 mM sodi
1 answer:
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Answer: A) 0.0480 grams and B) 56.16 years.
Explanation: Half live is the time in which the amount of radioactive substance remains halve of its initial amount.
The formula we use for solving this type of problem is:
where, is the initial amount and N is the remaining amount of radioactive substance and n is the number of half lives.
where, T is the time and is half life.
A) from given data, = 2 g
T = 70 years
= 13 years
N= ?
n = 5.38
N = 0.0480 g
So, 0.0480 grams of the substance will be remaining after 70 years.
B) = 2 g
N = 0.1 g
T = ?
Let's first calculate the value of n for this.
Taking log to both sides:
n = 4.32
Half life is 13 years, so we can calculate the time as:
T = 56.16 years
So, it will take 56.16 years for the radioactive substance to decay from 2 g to 0.1 g.