The answer is , n<span>o, because there are not the same number of molecules in the product side as in the reactant side.
The law of conservation of matter says that the system remains the same throughout. The number of atoms, mass and energy must stay constant. If you look at your figure there are more white atoms on the left side than the right, this means that there was a loss and this should not be the case.
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Answer:
Frequency is <u>the number of waves</u> that move past a point during a specific amount of time. Frequency is measured in <u>Hertz</u>, and is classified as high, medium, or low. Frequency is interpreted as the <u>pitch</u> of a sound. Intensity refers to the <u>loudness</u> of a sound and is measured in <u>decibels</u>. Louder sounds <u>increase</u> the rate of nerve signals relayed to the brain.
Explanation:
Represent the motion in the number line.
Movement to the east is movement to the negative side. Movement to the west is movement to the positive side.
Total displacement = -680m + 430m - 620m = -870m
Total displacement = 860m to the east.
(a) The velocity ratio of the screw is 1570.8.
(b) The mechanical advantage of the screw is 785.39.
<h3>
Velocity ratio of the screw</h3>
The velocity ratio of the screw is calculated as follows;
V.R = 2πr/P
where;
- P is the pitch = 1/10 cm = 0.1 cm = 0.001 m
- r is radius = 25 cm = 0.25 m
V.R = (2π x 0.25)/(0.001)
V.R = 1570.8
<h3>Mechanical advantage of the screw</h3>
E = MA/VR x 100%
0.5 = MA/1570.8
MA = 785.39
Learn more about mechanical advantage here: brainly.com/question/18345299
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Answer:
a) v = 0.7071 v₀, b) v= v₀, c) v = 0.577 v₀, d) v = 1.41 v₀, e) v = 0.447 v₀
Explanation:
The speed of a wave along an eta string given by the expression
v = 
where T is the tension of the string and μ is linear density
a) the mass of the cable is double
m = 2m₀
let's find the new linear density
μ = m / l
iinitial density
μ₀ = m₀ / l
final density
μ = 2m₀ / lo
μ = 2 μ₀
we substitute in the equation for the velocity
initial v₀ = 
with the new dough
v = 
v = 1 /√2 \sqrt{ \frac{T_o}{ \mu_o} }
v = 1 /√2 v₀
v = 0.7071 v₀
b) we double the length of the cable
If the cable also increases its mass, the relationship is maintained
μ = μ₀
in this case the speed does not change
c) the cable l = l₀ and m = 3m₀
we look for the density
μ = 3m₀ / l₀
μ = 3 m₀/l₀
μ = 3 μ₀
v = 
v = 1 /√3 v₀
v = 0.577 v₀
d) l = 2l₀
μ = m₀ / 2l₀
μ = μ₀/ 2
v = 
v = √2 v₀
v = 1.41 v₀
e) m = 10m₀ and l = 2l₀
we look for the density
μ = 10 m₀/2l₀
μ = 5 μ₀
we look for speed
v = 
v = 1 /√5 v₀
v = 0.447 v₀
