The horizontal force applied is 160 N while the velocity is 2.03 m/s.
<h3>What is the speed of the car?</h3>
The work done by the car is obtained as the product of the force and the distance;
W = F x
F = ?
x = 30.0 m
W = 4,800 J
F = 4,800 J/30.0 m
F = 160 N
But F = ma
a = F/m
a = 160 N/2.30 ✕ 10^3-kg
a= 0.069 m/s
Now;
v^2 = u^2 + 2as
u = 0/ms because the car started from rest
v = √2as
v = √2 * 0.069 * 30
v = 2.03 m/s
Learn more about force and work:brainly.com/question/758238
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The force applied to pull the box up the ramp acts parallel to the incline is 8N
The force applied to pull the box is expressed as:
Fm is the moving force
Ff is the force of friction
Get the moving force and frictional fice
The force applied to pull the box up the ramp acts parallel to the incline = 5N + 3N = 8N
Hence the force applied to pull the box up the ramp acts parallel to the incline is 8N
Learn more here: brainly.com/question/17219637
There are times where the mass is less than the force of gravity or the gravitational pull. The gravitational pull will overpower the mass of the object, which is why you only notice the force of gravity and not the mass