If a diver displace water with a weight of 500N what is the upthrust on the diver?
1 answer:
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<h2>The man have to apply force of 160 N</h2>
Explanation:
The work done to lift the bag of weight mg through height 2.5 m is 400 J
The work done can be found by relation W = mg x h
Thus mg = =
= 160 N
Therefore the man have to apply the force of 160 N
Answer:
r = 0.11 m
Explanation:
The radius of the proton's resulting orbit can be calculated equaling the force centripetal (Fc) with the Lorentz force (), as follows:
(1)
<u>Where:</u>
<em>m: is the proton's mass = 1.67*10⁻²⁷ kg</em>
<em>v: is the proton's velocity</em>
<em>r: is the radius of the proton's orbit</em>
<em>q: is the proton charge = 1.6*10⁻¹⁹ C</em>
<em>B: is the magnetic field = 0.040 T </em>
Solving equation (1) for r, we have:
(2)
By conservation of energy, we can find the velocity of the proton:
(3)
<u>Where:</u>
<em>K: is kinetic energy</em>
<em>U: is electrostatic potential energy</em>
<em>ΔV: is the potential difference = 1.0 kV </em>
Solving equation (3) for v, we have:
Now, by introducing v into equation (2), we can find the radius of the proton's resulting orbit:
Therefore, the radius of the proton's resulting orbit is 0.11 m.
I hope it helps you!