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Oksana_A [137]
3 years ago
11

A person consumes a snack containing 14 food calories (14kcal). what is the power this food produces if it is to be "burned off"

due to exercise in 6 hours? (1 cal=4.186 J).
A. 9763 W
B. 2.7 W
C. 0.6 W
D. .0027 W
Physics
2 answers:
Inessa05 [86]3 years ago
8 0

Answer:

B) 2.7W

Explanation:

Converting Cal to Joule

        1 cal = 4.186J

        14 kcal = 14 x 1000 x 4.186

                     = 58604 J

Converting hour to seconds

             6 hours = 6 x 60 x 60 seconds

                           = 21600 seconds

Power is the time rate of doing work.

Power = Work/Time

P = (58604) / (21600)

P = 2.7W

max2010maxim [7]3 years ago
7 0

Answer:

D) 0.0027

Explanation:

Power is the rate of work that is power = work/time

we are given the following:

Work = 14kcal this is equal to 58.576 J

time = 6hours this is equal to 21600 seconds

therefore:

Power = 58.576/21600 = 0.0027W

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Which of the following are major problems with fission reactors?
ValentinkaMS [17]

Answer:

The correct answer is C: Disposal of radioactive waste.

Explanation:

During nuclear fission reactions, many intermediate radioisotopes are produced. For example, uranium releases different mass distribution isotopes and these isotopes emit radiations.

Most harmful isotopes for the environment are strontium and cesium because these have half-lives and an inclination of mixing in food chains.

When radioactive wastes are removed from nuclear reactors they flow towards the swimming pool and also have the tendency to isolate the short-lived isotopes from the environment.

Therefore, radioactive waste disposal has always remained a major problem

3 0
4 years ago
What is her initial acceleration if she is initially stationary and wearing steel-bladed skates that point in the direction of?
madreJ [45]
We will apply the Newton's second Law so the we will be able to find the acceleration.
F (tot) = ma
a = F(tot) /  m
a = 32.0 N / 65.0 kg = 0.492 m/s^2
Approximately 0.492 m/s^2 is her initial acceleration if she is initially stationary and wearing steel-bladed skates.

7 0
3 years ago
A frictionless pendulum of length of 3 m swings with an amplitude of 10o. At its maximum displacement, the potential energy of t
olchik [2.2K]
<h2>Option A is the correct answer.</h2>

Explanation:

For a simple pendulum we have at any position

             Total energy = Constant        

             Kinetic energy + Potential energy = Constant

At maximum displacement of pendulum, velocity is zero, hence kinetic energy is zero.

At maximum displacement the pendulum only have potential energy.

Given that maximum potential energy is 10 J.

 That is at any position                

                     Kinetic energy + Potential energy = 10 J

Now we need to find kinetic energy when potential energy is 5 J.

                     Kinetic energy + 5 J = 10 J

                     Kinetic energy = 5 J

Option A is the correct answer.

6 0
3 years ago
A car accelerates uniformly from rest to a speed of 23.7m/s in 6.5 seconds. Find the distance the
frez [133]

The car's average speed during that time is (23.7/2) = 11.85 m/s .

     Distance = (11.85 m/s) x (6.5 sec) = 77.025 meters .

5 0
4 years ago
What is the energy stored between 2 Carbon nuclei that are 1.00 nm apart from each other? HINT: Carbon nuclei have 6 protons and
Andrei [34K]

Answer:

A. 8.29\times 10^{-18}\ J

Explanation:

Given that:

p = magnitude of charge on a proton = 1.6\times 10^{-19}\ C

k = Boltzmann constant = 9\times 10^{9}\ Nm^2/C^2

r = distance between the two carbon nuclei = 1.00 nm = 1.00\times 10^{-9}\ m

Since a carbon nucleus contains 6 protons.

So, charge on a carbon nucleus is q = 6p=6\times 1.6\times 10^{-19}\ C=9.6\times 10^{-19}\ C

We know that the electric potential energy between two charges q and Q separated by a distance r is given by:

U = \dfrac{kQq}{r}

So, the potential energy between the two nuclei of carbon is as below:

U= \dfrac{kqq}{r}\\\Rightarrow U = \dfrac{kq^2}{r}\\\Rightarrow U = \dfrac{9\times10^9\times (9.6\times 10^{-19})^2}{1.0\times 10^{-9}}\\\Rightarrow U =8.29\times 10^{-18}\ J

Hence, the energy stored between two nuclei of carbon is 8.29\times 10^{-18}\ J.

8 0
3 years ago
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