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Oksana_A [137]
3 years ago
11

A person consumes a snack containing 14 food calories (14kcal). what is the power this food produces if it is to be "burned off"

due to exercise in 6 hours? (1 cal=4.186 J).
A. 9763 W
B. 2.7 W
C. 0.6 W
D. .0027 W
Physics
2 answers:
Inessa05 [86]3 years ago
8 0

Answer:

B) 2.7W

Explanation:

Converting Cal to Joule

        1 cal = 4.186J

        14 kcal = 14 x 1000 x 4.186

                     = 58604 J

Converting hour to seconds

             6 hours = 6 x 60 x 60 seconds

                           = 21600 seconds

Power is the time rate of doing work.

Power = Work/Time

P = (58604) / (21600)

P = 2.7W

max2010maxim [7]3 years ago
7 0

Answer:

D) 0.0027

Explanation:

Power is the rate of work that is power = work/time

we are given the following:

Work = 14kcal this is equal to 58.576 J

time = 6hours this is equal to 21600 seconds

therefore:

Power = 58.576/21600 = 0.0027W

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Consider two diffraction gratings. One grating has 3000 lines per cm, and the other one has 6000 lines per cm. Both gratings are
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Answer:

<em>The 6000 lines per cm grating, will produces the greater dispersion .</em>

Explanation:

A diffraction grating is an optical component with a periodic (usually one  that has ridges or rulings on their surface rather than dark lines) structure that splits and diffracts light into several beams travelling in different directions.

The directions of the light beam produced from a diffraction grating depend on the spacing of the grating, and also on the wavelength of the light.

For a plane diffraction grating, the angular positions of principle maxima is given by

(a + b) sin ∅n = nλ

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a+b is the distance between two consecutive slits

n is the order of principal maxima

λ is the wavelength of the light

From the equation, we can see that without sin ∅ exceeding 1, increasing the number of lines per cm will lead to a decrease between the spacing between consecutive slits.

In this case, light of the same wavelength is used. If λ and n is held constant, then we'll see that reducing the distance between two consecutive slits (a + b) will lead to an increase in the angle of dispersion sin ∅. So long as the limit of sin ∅ not greater that one is maintained.

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3 years ago
Suppose that a ball is released from the window of a train that is moving with constant velocity.  The path of the ball, as obse
barxatty [35]

True, the path of the ball, as observed from the train window, will be a horizontal straight line.

An object projected from a certain height has a parabolic path when observed from a fixed point.

However, if the reference point is moving at the same velocity as the object, the path of the object's motion appears to be a straight line.

When the ball is released from the window of the train, it will move at the same constant velocity as the train, and the path of the ball's motion observed from the train window will be a straight line.

Thus, we can conclude that the given statement is true. The path of the ball, as observed from the train window, will be a horizontal straight line.

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The concentration of a solution that contains 70g of H2SO4 in 0,28 dm³ of solution is?​
Simora [160]

Taking into account the definition of molarity, the concentration of a solution that contains 70 g of H₂SO₄ in 0,28 dm³ of solution is 2.5510 \frac{moles}{L}.

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

Molarity=\frac{number of moles}{volume}

Molarity is expressed in units \frac{moles}{L}.

<h3>This case</h3>

In this case, you have:

  • number of moles= 70 g×\frac{1 mole}{98 g}= 0.7143 moles, where 98 g/mole os the molar mass of H₂SO₄
  • volume= 0.28 dm³= 0.28 L (being 1 dm³= 1 L)

Replacing in the definition of molarity:

Molarity=\frac{0.7143 moles}{0.28 L}

Solving:

<u><em>Molarity= 2.5510 </em></u>\frac{moles}{L}

Finally, the concentration of a solution that contains 70 g of H₂SO₄ in 0,28 dm³ of solution is 2.5510 \frac{moles}{L}.

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