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Furkat [3]
3 years ago
14

If ?h°rxn and ?s°rxn are both negative values, what drives the spontaneous reaction and in what direction at standard conditions

?
Physics
1 answer:
irakobra [83]3 years ago
6 0

The release of free energy drives the spontaneous reaction.

Spontaneity can be <span>determined using the change in </span>Gibbs free energy (the thermodynamic potencial):

delta G=delta H – T*delta S

where delta H is the enthalpy and delta S is the entropy.

The direction (the sign) of delta G depends of the changes of enthalpy and entropy. If delta G is negative then the process is spontaneous.

In our case, both delta H and delta S are negative values, the process as said is spontaneous which means that it may proceed in the forward direction.

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Which part of the ear vibrates at the frequency of sound waves
olganol [36]
The ear drum vibrates

6 0
2 years ago
A transparent oil with index of refraction 1.28 spills on the surface of water (index of refraction 1.33), producing a maximum o
Veseljchak [2.6K]

To solve this problem we will apply the concepts related to the principle of destructive and constructive interference. Mathematically this expression can be given as

2nt = m\lambda

Here,

n = Index of refraction

t = Thickness

m = Order of the reflection

\lambda = Wavelength

We have all of this values, therefore replacing,

2(1.28)t = (1)(600nm)

t = 233nm    

Therefore the thickness of the oil slick is 233nm

3 0
3 years ago
A series RCL circuit is at resonance and contains a variable resistor that is set to 206Ω. The power dissipated in the circuit i
mash [69]

Answer:

Power dissipated in resistor 532 ohm is 0.503 watt

Explanation:

We have given in first case resistance R_1=206ohm

Power dissipated in this resistance is P_1=1.30watt

Power dissipated in the resistor is equal to P=\frac{v_{rms}}^2{R}

We have to find the power dissipated in the resistor is 1.30 watt

From the relation we can say that \frac{P_1}{P_2}=\frac{R_2}{R_1}

\frac{1.3}{P_2}=\frac{532}{206}

P_2=0.503watt

So power dissipated in resistor 532 ohm is 0.503 watt  

5 0
3 years ago
The addition of electron shells results in<br><br> shielding of electrons from the nucleus.
Pani-rosa [81]

Answer:

Addition of shells increases the distance of outer electrons from the nucleus.

Explanation:

Shielding effect is known as the attraction between the nucleus and an electron of any atom. In other words, it is the reduction in effective nuclear charge on an electron cloud.

Addition of electron shells results in the shielding of electron from nucleus.  As the number of electron shells increases then farther will be the electrons placed from the nucleus and hence it will become easier to expel the electrons from outer shells with only little amount of ionization energy.

So, the amount of ionization energy require will be indirectly proportional to the shielding effect because more the shielding of electrons from the nucleus less will be the ionization energy require to expel the electrons.

4 0
3 years ago
Why is it necessary to collimate the light source before using the prism to disperse the light?.
Sergeu [11.5K]

The reason to collimate the light source before utilizing the prism is that if white light enters the prism at various angles, some blue light will exit the prism at the same angle.

Prisms' Dispersion of Light. When light source travels through a triangular prism, these hues are frequently seen. The prism separates the white light source divided into its individual colors, which are red, orange, yellow, green, blue, and violet. Dispersion is the process through which visible light is divided into its various colors.

Since blue light has a shorter wavelength than red light and refracts more than the latter, it is bent more when white light enters a prism than red light.

Learn more about light source here

brainly.com/question/14459326

#SPJ4

5 0
9 months ago
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