The outer layer of space ships are covered with tiles primarily to protect the shuttle for entering back into the atmosphere. On re-entry space ships generally take a great deal of heat damage, as well as being worn down by the atmosphere.
Answer:
The current when the filament at room temperature is 11.84 A.
Explanation:
Given that,
Thermal coefficient of resistivity 
Initial temperature = 293 K
Voltage = 140 Volt
Final temperature = 2900 K
Current = 0.95 A
Suppose we find the numerical value of the current when the filament is at room temperature
So, We use the equation of resistance of a material changes with temperature
....(I)
Using ohm's law for value of resistance
Put the value of resistance in the equation (I)
Put the value into the formula
Hence, The current when the filament at room temperature is 11.84 A.
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Given Information:
Diameter = d = 100 m
Required Information:
Period = T = ?
Answer:
Period = T = 14.2 seconds
Explanation:
We know that a station revolving at an angular velocity ω, have an acceleration given by
α = ω²r
Where ω is angular velocity and r is the radius of cylindrical space station.
Normal gravity means α = g = 9.8 m/s²
ω² = α/r
ω = √(α/r)
The radius is given by
r = d/2
r = 100/2
r = 50 m
ω = √(9.8/50)
ω = 0.4427 rad/sec
We also know that
ω = 2πf
f = ω/2π
f = 0.4427/2π
f = 0.0704 rev/sec
Finally time period is given by
T = 1/f
T = 1/0.0704
T = 14.2 sec
Therefore, the rotation period is 14.2 seconds.
