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OLga [1]
3 years ago
8

An object with a mass of 1 kg is attached to one end of a cord 10 m long. The cord will break if its tension exceeds 10 N. The o

bject is swung in a
horizontal circle on a frictionless surface. The other end of the cord remains fixed. Find the maximum speed the object can attain without breaking
the cord.
10 m/s
20 m/s
25 m/s
15 m/s
Physics
1 answer:
faust18 [17]3 years ago
3 0

Answer:

10 m/s

Explanation:

∑F = ma

T = m v² / r

10 N = (1 kg) v² / (10 m)

v = 10 m/s

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A jumbo jet must reach a speed of 360 km/h on the runway for takeoff. What is the lowest constant acceleration needed for takeof
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The lowest constant acceleration needed for takeoff from a 1.80 km runway is 2.8 m/s².

To find the answer, we need to know about the Newton's equation of motion.

<h3>What's the Newton's equation of motion to find the acceleration in term of initial velocity, final velocity and distance?</h3>
  • The Newton's equation of motion that connects velocity, distance and acceleration is V² - U²= 2aS
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<h3>What's the acceleration, if the initial velocity, final velocity and distance are 0 m/s, 360km/h and 1.8 km respectively?</h3>
  • Here, S= 1.8 km or 1800 m, V= 360km/h or 100m/s , U= 0 m/s
  • So, 100²-0= 2×a×1800

=> 10000= 3600a

=> a= 10000/3600 = 2.8 m/s²

Thus, we can conclude that the lowest constant acceleration needed for takeoff from a 1.80 km runway is 2.8 m/s².

Learn more about the Newton's equation of motion here:

brainly.com/question/8898885

#SPJ4

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