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4 years ago

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Solar cell A produces 100 joules of energy, when a light source is shown on it for 3 minutes. Solar cell B produces 200 joules o

f energy when the same light source is shown on it for 5 minutes. Which solar cell works better? A) Solar cell B, because it produces more energy. B) Solar cell B, because it generates more power. C) Solar Cell A, because it produces energy quicker. D) Solar Cell A, because it generates a greater wattage. Eliminate

2 answers:

dangina [55]3 years ago

6 0

The Answer is B

Explanation:

ella [17]4 years ago

3 0

Answer: (B). Solar cell B, because it generates more power.

Explanation:

Given that,

For solar cell A

Energy = 100 Joules

Time = 3 minutes = 180 sec

Power of cell A

Power = Energy/Time

$P = \dfrac{100}{180}\ Watt$

$P = 0.55\ Watt$

For solar cell B

Energy = 200 joules

Time = 5 minutes = 300 sec

Power of cell B

Power = Energy/Time

$P = \dfrac{200}{300}\ watt$

$P = 0.66\ Watt$

Hence, Solar cell B, because it generates more power.

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Define average atomic mass and explain how it is calculated

Flauer [41]

Answer:

The average atomic mass of an element is the sum of masses of it's isotopes

Each are multiplied by it's natural abundance

Explanation:

The average atomic mass of an element is the sum of masses of it's isotopes

Each are multiplied by it's natural abundance

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3 years ago

In the Compton effect, the wavelength of the scattered photon is __________ the wavelength of the incident photon.

SOVA2 [1]

Answer:

he wavelength is different (greater) than the wavelength of the incident photon

Explanation:

The Compton effect is the scattering of a photon by an electron, this process is analyzed using the conservation of momentum, in which we assume that initially the electron is at rest and after the collision it recedes, therefore the energy of the incident photon decreases and consequently its wavelength changes

To complete the sentence we use the wavelength is different (greater) than the wavelength of the incident photon

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3 years ago

To understand the decibel scale. The decibel scale is a logarithmic scale for measuring the sound intensity level. Because the d

frez [133]

The question is incomplete. Here is the complete question.

To understand the decibel scale. The decibel scale is a logarithmic scale for measuring the sound intensity level. Because the decibel scale is logarithmic, it changes by an additive constant when the intensity when the intensity as measured in W/m² changes by a multiplicative factor. The number of decibels increase by 10 for a factor of 10 increase in intensity. The general formula for the sound intensity level, in decibels, corresponding to intensity I is

$\beta=10log(\frac{I}{I_{0}} )dB$ ,

where $I_{0}$ is a reference intensity. for sound waves, $I_{0}$ is taken to be $10^{-12} W/m^{2}$ . Note that log refers to the logarithm to the base 10.

Part A: What is the sound intensity level β, in decibels, of a sound wave whose intensity is 10 times the reference intensity, i.e. $I=10I_{0}$ ? Express the sound intensity numerically to the nearest integer.

Part B: What is the sound intensity level β, in decibels, of a sound wave whose intensity is 100 times the reference intensity, i.e. $I=100I_{0}$ ? Express the sound intensity numerically to the nearest integer.

Part C: Calculate the change in decibels ( $\Delta \beta_{2},\Delta \beta_{4}$ and $\Delta \beta_{8}$ ) corresponding to f = 2, f = 4 and f = 8. Give your answer, separated by commas, to the nearest integer -- this will give an accuracy of 20%, which is good enough for sound.

Answer and Explanation: Using the formula for sound intensity level:

A) $I=10I_{0}$

$\beta=10log(\frac{10I_{0}}{I_{0}} )$

$\beta=10log(10 )$

β = 10

<u>The sound Intensity level with intensity 10x is </u><u>10dB</u>.

B) $I=100I_{0}$

$\beta=10log(\frac{100I_{0}}{I_{0}} )$

$\beta=10log(100)$

β = 20

<u>With intensity 100x, level is </u><u>20dB</u>.

C) To calculate the change, take the f to be the factor of increase:

For $\Delta \beta_{2}$ :

$I=2I_{0}$

$\beta=10log(\frac{2I_{0}}{I_{0}} )$

$\beta=10log(2)$

β = 3

For $\Delta \beta_{4}$ :

$I=4I_{0}$

$\beta=10log(\frac{4I_{0}}{I_{0}} )$

$\beta=10log(4)$

β = 6

For $\Delta \beta_{8}$ :

$I=8I_{0}$

$\beta=10log(\frac{8I_{0}}{I_{0}} )$

β = 9

Change is

$\Delta \beta_{2},\Delta \beta_{4}$ , $\Delta \beta_{8}$ = 3,6,9 dB

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3 years ago

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vovangra [49]

Answer:

a = 8.951 m/s²

Explanation:

given,

angle = 0.52 radians

μ_s = 0.84

μ_k = 0.48

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F + f = m a

mg sin θ + μk mg cos θ = m a

a = g sin θ + μk g cos θ

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4 years ago

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