Hey there!
![a \ student \ is \ able \ to \ lift \ a \ 500(n) \\ weight \ by \ applying \ only \ 100(n) \\ \\ so, \ this \ info \ here, \ we \ simply \ divide \ by \\ how \ much \ this \ kid \ lifted, \ by \ the \ weight \ he/she \\ \ is \ applying. \\ \\ \left[\begin{array}{ccc}\boxed{\boxed{500(n)/100(n)}}\end{array}\right] \\ \\ and \ from \ this,\ your \ answer \ would \ \\ conclude \ to \ be \ (5) \\ \\ \boxed{5} \ would \ be \ your \ answer!](https://tex.z-dn.net/?f=%20a%20%5C%20student%20%20%5C%20is%20%5C%20able%20%5C%20to%20%5C%20lift%20%5C%20a%20%5C%20500%28n%29%20%5C%5C%20weight%20%5C%20by%20%5C%20applying%20%5C%20only%20%20%5C%20100%28n%29%20%5C%5C%20%5C%5C%20so%2C%20%5C%20this%20%5C%20info%20%5C%20here%2C%20%5C%20we%20%5C%20simply%20%5C%20divide%20%5C%20by%20%5C%5C%20how%20%5C%20much%20%5C%20this%20%5C%20kid%20%5C%20lifted%2C%20%5C%20by%20%5C%20the%20%5C%20weight%20%5C%20he%2Fshe%20%5C%5C%20%5C%20is%20%5C%20applying.%20%5C%5C%20%5C%5C%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cboxed%7B%5Cboxed%7B500%28n%29%2F100%28n%29%7D%7D%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%20%5C%5C%20and%20%5C%20from%20%5C%20this%2C%5C%20your%20%5C%20answer%20%5C%20would%20%5C%20%5C%5C%20conclude%20%5C%20to%20%5C%20be%20%5C%20%285%29%20%5C%5C%20%5C%5C%20%5Cboxed%7B5%7D%20%5C%20would%20%5C%20be%20%5C%20your%20%5C%20answer%21)
Hope this helps you!
Hope this helps you!
A tow truck exerts a net horizontal force of 1050 N on a 760-kg car. What is the acceleration of the car during this time?
1 answer:
We can solve the problem by using Newton's second law of motion:
where
F is the net force applied to the object
m is the object's mass
a is the acceleration of the object
In this problem, the force applied to the car is F=1050 N, while the mass of the car is m=760 kg. Therefore, we can rearrange the equation and put these numbers in, in order to find the acceleration of the car:
The equation also tells us that the acceleration and the force have same directions: therefore, since the force exerted on the car is horizontal, the correct answer is
<span>B) 1.4 m/s2 horizontally.</span>
where
F is the net force applied to the object
m is the object's mass
a is the acceleration of the object
In this problem, the force applied to the car is F=1050 N, while the mass of the car is m=760 kg. Therefore, we can rearrange the equation and put these numbers in, in order to find the acceleration of the car:
The equation also tells us that the acceleration and the force have same directions: therefore, since the force exerted on the car is horizontal, the correct answer is
<span>B) 1.4 m/s2 horizontally.</span>
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