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MatroZZZ [7]
4 years ago
7

Find the velocity of the student using KE= 1/2 mv^2. A 50-kilogram student is running and has 225 joules of kinetic energy. The

student’s speed is meters/second
Physics
1 answer:
defon4 years ago
3 0
225 = 1/2 (50) (v2)
225 = 25 (v2)
225/25 = v2
9 = v2
√9 = v
v = 3 m/s
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Which statement is true regarding flexibility? A. joint's range of motion cannot be maintained with age. b.A joint's range of mo
Alex777 [14]
<span>the statement that is true regarding flexibility is : b. a joint's range of motion will be lost if the joint is not used regularly. Our body is like a machine. If we not constantly heat it up, our body will be more prone to injury. We can see that the old people who lived within the tribe in the middle of the mountain are far stronger than the one who lived in the city.</span>
3 0
3 years ago
Read 2 more answers
A proposed space station includes living quarters in a circular ring 50.0 m in diameter. At what angular speed should the ring r
mel-nik [20]
Given that the space station is free of gravitational force, it is required that it spins an certain speed to acquire centripetal acceleration.

In this case, you want that the centripetal acceleration, Ac, equals g (gravitational acceleration on the earth), becasue this will cause a centripetal force equal to the weight on earth.

The formula for centripetal acceleration is Ac = [angular velocity]^2*R

where R = [1/2]50.0m = 25.0 m

Ac = 9.81 m/s^2

=> [angular velocity]^2 = Ac/R = 9.81m/s^2v/ 25.0m = 0.3924 (rad/s)^2

[angular velocity] = √(0.3924) rad/s = 0.63 rad/s

Answer: 0.63 rad/s

 

5 0
3 years ago
Suppose a vector v makes an angle theta with respect to the y axis, what could be the x and y components of the vector v
gtnhenbr [62]

If the angle between the vector and the y-axis is  Θ ,
then the y-component of the vector is

                   (length of the vector) times  cosine( Θ ),

and the x-component of the vector is

                   (length of the vector) times  sine( Θ ) .

8 0
3 years ago
An object accelerates from rest to 93 m/s over a distance of 49 m. What acceleration did it experience?
Maksim231197 [3]

Answer:

88.3ms {}^{ - 2}

or 88.3m/s^2

Explanation:

Using suvat where we list everything that we are given

s=49m

u=0m/s

v=93m/s

a=?

t=we are not given this value, so we don't use

using a formula that doesn't involve time:

v {}^{2}  = u {}^{2}  + 2as

rearranging to find acceleration by subtracting u^2 on both sides

v {}^{2}  - u {}^{2}  = 2as

then dividing 2s on both sides

\frac{v {}^{2} - u {}^{2}  }{2s}  = a

\frac{(93) {}^{2}  - (0) {}^{2} }{2 \times(49) }  = 88.3ms {}^{ - 2}

so the acceleration is 88.3ms^-2 (1dp)

3 0
3 years ago
How does the density of most metals compare to most non metals?
Neko [114]
Harder. Not compressible(unless using an extremely strong force). Non-metal have more of a chance of breaking than metals.
8 0
3 years ago
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