Find the velocity of the student using KE= 1/2 mv^2. A 50-kilogram student is running and has 225 joules of kinetic energy. The
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Answer:
The speed of the stone when it is 4.66 m higher is 236.057 m/s.
Explanation:
Given the initial velocity and vertical distance, we can use the fourth kinematic equation () to find v final, or the v to the left of the equal sign. We know
(initial velocity) is 24.7 m/s, y (change in vertical distance) is 4.66 m, and a is another way to write g (acceleration due to gravity), or 9.8
.
From here you could plug in the values and solve for v final, but to make the solving process simpler, we can simplify the given equation, <em>then </em>plug in the known values.
To isolate v final, we can take the square root of and do the same to the right side of the equation. Therefore, we can find v final with:
, where v initial is outside of the square root because it squared...
If we plug in the known values to the simplified equation, we get:
The final answer is 236.057 m/s.