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Mrac [35]
3 years ago
10

The motion of an orbiting satellite can be described by the same motion characteristic of any object in uniform circular motion.

The centripetal force acting toward the center of the circle, in this case, is supplied by
Physics
1 answer:
densk [106]3 years ago
6 0

The force exerted by Earth plays the role of centripetal force.


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How does work done on an object affect its kinetic energy
Alexus [3.1K]

According to the work-energy theorem, the work done on an object by a net force equals the change in kinetic energy of the object. Essentially kinetic energy is the energy used for motion. Interestingly, as work is done on an object, potential energy can be stored in that object. A moving object has kinetic energy because work has been done on it. When work is done energy in one form is transferred to the kinetic energy of the moving object. To stop the object again, the same amount of work would have to be done to bring it back to rest.

5 0
3 years ago
What is the acceleration of a 10.5 kg mass pushed by a 50.5 n force
Lina20 [59]

Answer:4.8 m/s^2

Explanation:

mass=10.5kg

Force=50.5N

Acceleration =force ➗ mass

Acceleration =50.5 ➗ 10.5

Acceleration =4.8 m/s^2

8 0
4 years ago
What total distance will a sound wave travel in air in 3.00 seconds at stp?
dimaraw [331]
At stp conditions (T=0^{\circ}C), the speed of sound is
v=331.2 m/s
The sound wave moves by uniform motion, so we can use the basic relationship between space, time and velocity:
S=vt
where S is the distance covered by the sound wave in a time t. In our problem, t=3.00 s, therefore the distance covered by the sound wave is
S=vt=(331.2 m/s)(3.00 s)=993.6 m
4 0
3 years ago
A ball rolls from x = - 5m to x = 0m in 1 second . What was its average velocity? (Units = m/s) Don't forget: velocities and dis
katrin2010 [14]

Answer:

+ 5 m/s

Explanation:

change in displacement = ΔX=final position - initial position

                                            ΔX = 0-(-5) =0+5 =+ 5 m

average velocity =  ΔX/t

                             = +5/1

                             = + 5 m/s

positive sign shows that ball rolls towards right

8 0
3 years ago
What is the strength of the electric field in a region where the electric potential is constant?
Roman55 [17]

Answer:

Where the electric potential is constant, the strength of the electric field is zero.

Explanation:

As a test charge moves in a given direction, the rate of change of the electric potential of the charge gives the potential gradient whose negative value is the same as the value of the electric field. In other words, the negative of the slope or gradient of electric potential (V) in a direction, say x, gives the electric field (Eₓ) in that direction. i.e

Eₓ = - dV / dx        ----------(i)

From equation (i) above, if electric potential (V) is constant, then the differential (which is the electric field) gives zero.

<em>Therefore, a constant electric potential means that electric field is zero.</em>

4 0
3 years ago
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