DE which is the differential equation represents the LRC series circuit where
L d²q/dt² + Rdq/dt +I/Cq = E(t) = 150V.
Initial condition is q(t) = 0 and i(0) =0.
To find the charge q(t) by using Laplace transformation by
Substituting known values for DE
L×d²q/dt² +20 ×dq/dt + 1/0.005× q = 150
d²q/dt² +20dq/dt + 200q =150
Answer:
q = C V charge on 1 capacitor
q = 1 * 10E-6 * 110 = 1.1 * 10E-4 C per capacitor
N = Q / q = 1 / 1.1 * 10E-4 = 9091 capacitors
As charges move in a closed loop, they gain as much energy as they lose.
<h3>What is principle of
conservation of energy?</h3>
- According to the principle of conservation of energy, in a closed or isolated system, the total energy of the system is always conserved.
- The energy gained by the particles or charges in a closed system is equal to the energy lost by the charges.
Thus, we can conclude the following based on principles of conservation of energy;
- As charges move in a closed loop, they gain as much energy as they lose.
Learn more about conservation of energy here: brainly.com/question/166559
