The mass of chlorine gas produced by 14.5 grams of sodium chloride is 10.42 g.
The mass of chlorine gas produced by 14.5 grams of sodium chloride is 8.81 g.
The given parameters;
- <em>mass of the sodium chloride, = 14.5 g</em>
- <em>2NaCl(s) + F2(g) → 2NaF(s) + Cl2(g)</em>
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In the reaction above, we can deduce the following;
molecular mass of 2Nacl = 2(58.44) = 116.88 g
molecular mass of 2NaF = 2(42) = 84 g
molecular mass of Cl2 = 71 g
The mass of sodium fluoride produced by 14.5 grams of sodium chloride is calculated as follows;
116.88 g of NaCl --------------- 84 g of NaF
14.5 g of NaCl ------------------- ?
The mass of chlorine gas produced by 14.5 grams of sodium chloride is calculated as follows;
116.88 g of NaCl --------------- 71 g of Cl2
14.5 g of NaCl ------------------- ?
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Percent (%) Composition of CuO
Cu = 1 x 50g - Multiply by one as there is one Cu
O = 1 x 12.5g - Multiply by one as there is one O
CuO = 62.5g
% for Cu = 50g over 62.5 multiplied by 100 = 80%
% for O = 12.5g over 62.5 multiplied by 100 = 20%
Final Answer :
<em>Percent (%) Composition of CuO = </em>80% (Cu) & 20% (O)
Balanced chemical equation for the reaction is:
2S
(g) + (g)+ 2
O (l) ⇒
Moles of formed is 5.75 moles.
Moles of oxygen used is 5.75 moles in the reaction.
Explanation:
Data given:
moles of S = 11.5 moles
moles of = ?
Moles of needed =?
balanced equation with states of matter =?
Balanced chemical reaction under STP condition is given as:
2S(g) + (g) + 2O (l) ⇒
From the balanced reaction 2 moles of sulphur dioxide reacted to form 1 mole of sulphuric acid:
so, from 11.5 moles of S, x moles of is formed
2x = 11.5
x = 5.75 moles of sulphuric acid formed.
From the balanced reaction 1 mole of oxygen reacted to form 1 mole of sulphuric acid.
when 11.5 moles of Sulphur dioxide reacted then oxygen in the reaction is 5.75 moles.
Answer:
Mass = 4.6 g
Explanation:
Given data:
Number of molecules of sucrose = 8.1 ×10²¹ molecules
Mass of sucrose = ?
Solution:
First of all we will calculate the number of moles by using Avogadro number.
1 mole × 8.1 ×10²¹ molecules / 6.022×10²³ molecules
1.35 × 10⁻² mol
Mass of sucrose:
Mass = number of moles × molar mass
Molar mass = 342.3 g/mol
Mass = 1.35 × 10⁻² mol ×342.3 g/mol
Mass = 462.1 × 10⁻² g
Mass = 4.6 g
