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lianna [129]
3 years ago
13

Koleman just received a 6% raise in salary. Before the raise he was making $52,000 per year. How much more will Koleman earn nex

t year?
Mathematics
2 answers:
pogonyaev3 years ago
7 0

$52,000 + 6% = $55,120

If this helped you, would you mind answering one of my recent questions? Thanks!

worty [1.4K]3 years ago
4 0

Answer:

Koleman will earn $55,120.00 more making his earning for both years $107,120.00

Step-by-step explanation:

Because he is getting a 6% raise, you need to multiply 1.06 and $52,000(so you don't waste time adding .06) to get $55,120.00

If you want to find out how much Koleman made in both years, then simply add his earnings for this year with his earnings for next year.

Hope this helps!

-Iv

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Sand Dune Landforms

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What is the length of BC in the right triangle below 21 and 72
sleet_krkn [62]
Im guessing 21 and 72 are the side lengths for the triangle?

Alright, so since it's a right triangle you can use the Pythagorean theorem or a^2+b^2=c^2

Since i cant see the picture, im going to use some general math <span>so i</span> can figure out if those two sides are the legs or if one of them is the hypotenuse
Alright 
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Step-by-step explanation:

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There are 10 apples in the fridge and 2 of them are bad. if you grab 3 apples, what is the expected number of bad apples
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Imagine an experiment having three conditions and 20 subjects within each condition. The mean and variances of each condition ar
xxTIMURxx [149]

Answer:

1. Mean square B= 5.32

2. Mean square E= 16.067

3. F= 0.33

4. p-value: 0.28

Step-by-step explanation:

Hello!

You have the information of 3 groups of people.

Group 1

n₁= 20

X[bar]₁= 3.2

S₁²= 14.3

Group 2

n₂= 20

X[bar]₂= 4.2

S₂²= 17.2

Group 3

n₃= 20

X[bar]₃= 7.6

S₃²= 16.7

1. To manually calculate the mean square between the groups you have to calculate the sum of square between conditions and divide it by the degrees of freedom.

Df B= k-1 = 3-1= 2

Sum Square B is:

∑ni(Ÿi - Ÿ..)²

Ÿi= sample mean of sample i ∀ i= 1,2,3

Ÿ..= general mean is the mean that results of all the groups together.

General mean:

Ÿ..= (Ÿ₁ + Ÿ₂ + Ÿ₃)/ 3 = (3.2+4.2+7.6)/3 = 5

Sum Square B (Ÿ₁ - Ÿ..)² + (Ÿ₂ - Ÿ..)² + (Ÿ₃ - Ÿ..)²= (3.2 - 5)² + (4.2 - 5)² + (7.6 - 5)²= 10.64

Mean square B= Sum Square B/Df B= 10.64/2= 5.32

2. The mean square error (MSE) is the estimation of the variance error (σ_{e}^2 → S_{e} ^{2}), you have to use the following formula:

Se²=<u> (n₁-1)S₁² + -(n₂-1)S₂² + (n₃-1)S₃²</u>

                        n₁+n₂+n₃-k

Se²=<u> 19*14.3 + 19*17.2 + 19*16.7 </u>= <u>  915.8   </u>  = 16.067

                 20+20+20-3                  57

DfE= N-k = 60-3= 57

3. To calculate the value of the statistic you have to divide the MSB by MSE

F= \frac{Mean square B}{Mean square E} = \frac{5.32}{16.067} = 0.33

4. P(F_{2; 57} ≤ F) = P(F_{2; 57} ≤ 0.33) = 0.28

I hope you have a SUPER day!

3 0
3 years ago
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