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k0ka [10]
3 years ago
9

Activity

Physics
1 answer:
qwelly [4]3 years ago
6 0

Answer:Eating. Your muscles in your arms and mouth use energy to feed itself. Then your body digest the food which also takes energy.

Sleep. When your tired, you don’t have much energy. It is said that you use more energy while your sleeping. But how do you become energized if you were using even more energy than before?

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Who sided with the French
Step2247 [10]

The French were helped by the Hurons

5 0
3 years ago
Read 2 more answers
According to Newton’s law of universal gravitation, which statements are true? As we move to higher altitudes, the force of grav
Sliva [168]

According to Newton’s law of universal gravitation, as we move to higher altitudes, the force of gravity on us decreases and as we gain mass, the force of gravity on us increases both are the true statement.  

<u>Explanation:  </u>

Newton law of universal gravity extends gravity beyond the earth's surface. This gravity depends on the masses directly and inverse to the distance square between their centers.

                                         F=G \frac{M \times m}{r^{2}}

Where,

F – Force, G – gravitational constant, M and m – masses in kg, r – distance in meters.

Since force is proportional to the masses of interacting objects. If the mass of any one object increases, gravity between them also gets increased. When moving to higher altitude, force decreases as the distance is inverse proportion to gravity.

4 0
3 years ago
Read 2 more answers
A carnot heat engine receives 600 kj of heat from a source of unknown temperature and rejects 175 kj of it to a sink at 20°c. de
oee [108]

(b) 71%

The thermal efficiency of a Carnot heat engine is given by:

\eta = \frac{W}{Q_{in}}

where

W is the useful work done by the engine

Q_{in} is the heat in input to the machine

In this problem, we have:

Q_{in}=600 kJ is the heat absorbed

W=600 kJ-175 kJ=425 kJ is the work done (175 kJ is the heat released to the sink, therefore the work done is equal to the difference between the heat in input and the heat released)

So, the efficiency is

\eta = \frac{425 kJ}{600 kJ}=0.71 = 71\%

(a) 737^{\circ}C

The efficiency of an engine can also be rewritten as

\eta = 1-\frac{T_C}{T_H}

where

T_C is the absolute temperature of the cold sink

T_H is the temperature of the source

In this problem, the temperature of the sink is

T_C = 20^{\circ}C + 273=293 K

So we can re-arrange the equation to find the temperature of the source:

T_H = \frac{T_C}{1-\eta}=\frac{293 K}{1-0.71}=1010 K\\T_H = 1010 K - 273=737^{\circ}C

7 0
3 years ago
Q1=-q2=q3=2.10^-8 đặt tại A,B,C .tìm lực điện tổng hợp tác dụng lên q4=2.10^-8 đặt tại D sao cho ANCD là hình
KiRa [710]

Answer:

Wala ko ka sabot ana oy sorry

5 0
3 years ago
A 2000 kg streetcar parked in a lot has a larger momentum than a 1000 kg car going 25 meters per second on the highway.
Arturiano [62]

Answer:

Other than the fact that momentum is a "vector" quantity I wouldn't know.

If the car had a momentum opposite to the chosen positive direction then its total momentum would be negative.

7 0
3 years ago
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