Answer:
friction
Explanation:
the road is the pathway for the vehicle so the tures create friction to stay sturdie
Answer:
<em>The displacement of the object is -8 m</em>
Explanation:
<u>Displacement</u>
The displacement of a moving object can be calculated as the area under (or above) the graph of velocity vs time.
If the area is below the y-axis, then the displacement is negative. Otherwise is positive.
It's important to differentiate displacement from distance. Displacement takes into consideration the direction of the movement. Distance does not and it's always positive.
From the graph provided, we can see the velocity from t=12 s from t=16 s is negative, and the displacement will also be negative.
The displacement is calculated as the area of the triangle with base b=16-12= 4 seconds and height = -4 m/s, thus:

The displacement of the object is -8 m
Answer:
0.54 sec.
Explanation:
The Speed: <u>2.4 m/seconds</u>
The Distance: <u>1.3 m</u>
So time = Distance/Speed
Time = <u>1.3 / 2.4</u>
THE ANSWER WILL BE 0.54 seconds.
The correct answer is D. The bicycle is not in motion.
In the position-time graph we can see that de position of the cycle hasn't changed when the time has changed (e.g. when time changes from 2s to 3s, the position remains 3m). Therefore, we can conclude that the cycle is not moving, and therefore answer D. is correct.
Answer:
Explanation:
Height of building
H = 6m
Horizontal speed of first balloon
U1x = 2m/s
Second ballot is thrown straight downward at a speed of
U2y = 2m/s
Time each gallon hits the ground
Balloon 1.
Using equation of free fall
H = Uoy•t + ½gt²
Uox = 0 since the body does not have vertical component of velocity
6 = ½ × 9.8t²
6 = 4.9t²
t² = 6 / 4.9
t² = 1.224
t = √1.224
t = 1.11 seconds
For second balloon
H = Uoy•t + ½gt²
6 = 2t + ½ × 9.8t²
6 = 2t + 4.9t²
4.9t² + 2t —6 = 0
Using formula method to solve the quadratic equation
Check attachment
From the solution we see that,
t = 0.9211 and t = -1.329
We will discard the negative value of time since time can't be negative here
So the second balloon get to the ground after t ≈ 0.92 seconds
Conclusion
The water ballon that was thrown straight down at 2.00 m/s hits the ground first by 1.11 s - 0.92s = 0.19 s.