a volleyball is hit upward with an initial velocity of 7.5 m/s. calculate the displacement of the volleyball when its final velo
1 answer:
Answer:
The displacement of the volleyball is 2.62 m
Explanation:
Given;
initial velocity of the volleyball, u = 7.5 m/s
final velocity of the volleyball, v = 2.2 m/s
displacement of the volleyball, d = ?
Apply the following kinematic equation;
v² = u² - 2gd
2gd = u² - v²
Therefore, the displacement of the volleyball is 2.62 m
You might be interested in
Answer:
The total pressure of the solution is 598.66 torr
while the vapor pressure of the components is vapor pressure of benzene is =502 torr and that of toluene = 96.6 tor
Explanation:
To solve this question, we need to look at the known variables, the unknown variables, and then we select the appropriate relations between the known variables and the unknown
Here we have the temperature of the gases t = 80°C
the pressures of benzene = 753 torr
the pressures of toluene = 290 torr
mole fraction of benzene in solution = 2/3
mole fraction of toluene in solution = 1/3
the unknown variables = composition of the solution and the total pressure of the solution
From here given the known variables and the required variables, the appropriate relation bstween the known and unknown variables is Route's Law
Raoult's relates the vapor pressure of a mixture of gases to the mole fraction of solute gases introduced in the gas solution. Raoult's Law is expressed by the formula: Psolution = Χsolvent1×Psolvent1 + Χsolvent2×Psolvent2+ ... .
where. Psolution = vapor pressure of the solution and
Χsolvent1 = mole fraction of solvent 1
Psolvent1 = vapor pressure of solvent1
Thus we have by Raoult's Law
=
×
+
×
which is =2/3×753 + 1/3×290 = 502 + 96.6 = 598.66 torr
and composition vapor pressure of benzene is 502 torr
while the composition vapor pressure of toluene is 96.6 torr