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3 years ago

A spring has a spring constant of 90N/m.How much potential energy does it store when stretched by 2 cm?

Physics

1 answer:

il63 [147K]3 years ago

5 0

Answer:

The potential energy stored in the spring is 0.018 J.

Explanation:

Given;

spring constant, k = 90 N/m

extension of the spring, x = 2 cm = 0.02 m

The potential energy stored in the spring is calculated as;

U = ¹/₂kx²

where;

U is the potential energy stored in the spring

Substitute the given values in the equation above;

U = ¹/₂ x 90 N/m x (0.02 m)²

U = 0.018 J

Therefore, the potential energy stored in the spring is 0.018 J.

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Answer:

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3 years ago

Marc and Linh stretch out a long spring on the classroom floor. Marc holds one end of the spring still. Linh creates waves in th

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The speed of the wave created by Linh in the spring by moving the other end right and left with a frequency of 2 Hz is 1m/s.

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The speed of a wave can be calculated by using the following formula:

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According to this question, Linh creates waves in the spring by moving the other end right and left with a frequency of 2 Hz. If wave crests are 0.5 m apart, the speed can be calculated as follows:

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2 years ago

I was driving along at 20 m/s, trying to change a CD and not watching where I was going. When I looked up, I found myself 45 m f

cricket20 [7]

Answer:

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First we have to find the time required for train to travel 60 meters and impact the car, this is an uniform linear motion:

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The reaction time of the driver before starting to accelerate was 0.50 seconds. So, remaining time for driver is 1.5 seconds.

Now, we have to calculate the distance traveled for the driver in this 0.5 seconds before he start to accelerate. Again, is an uniform linear motion:

$d=vt\\d=20\frac{m}{s}(0.5s)=10m$

The driver cover 10 meters in this 0.5 seconds. So, the remaining distance to be cover in 1.5 seconds by the driver are 35 meters. We calculate the minimum acceleration required by the car in order to cross the tracks before the train arrive, Since this is an uniformly accelerated motion, we use the following equation:

$d=v_0t+\frac{1}{2}at^2\\a=\frac{2(d-v_0t)}{t^2}\\a=\frac{2(35m-20\frac{m}{s}*1.5s}{(1.5s)^2}\\a=4.44\frac{m}{s^2}$

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3 years ago

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3 years ago

PLZZZZZ ANSWER Which example describes a nonrenewable resource?

Zepler [3.9K]

Answer:

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So, the answer is D.

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3 years ago

Read 2 more answers